从查询结果中删除重复数据

Question

我有以下查询:

 select 
    C.ClientID,
    C.FirstName + ' ' + C.LastName as ClientName,
    CAST(V.StartDate as date) as VisitDate,
    count(*) as 'Number of Visits'
 from
    Visit V
 Inner Join Client C on
    V.ClientID = C.ClientID
 group by 
    C.ClientID,
    C.FirstName + ' ' + C.LastName,
    CAST(V.StartDate as date)
 having
    count(*) > 3
 order by
    C.ClientID, 
    CAST(V.StartDate as date)

给出了以下结果(如果有人想知道,名字是假的)

 ClientID   ClientName            VisitDate      Number of Visits
 75         Kay Taylor            2016-06-07     4
 372         Moses Mcgowan       2016-09-03      4
 422         Raven Mckay         2016-03-11      4
 422         Raven Mckay         2016-06-14      4
 679         Ulysses Booker      2016-01-09      4
 696         Timon Turner        2016-07-06      4
 1063        Quyn Wall           2016-06-25      4
 1142        Garth Moran         2016-11-20      4
 1142        Garth Moran         2016-11-21      4
 1563        Hedley Gutierrez    2016-01-07      4
 1563        Hedley Gutierrez    2016-01-17      4
 1563        Hedley Gutierrez    2016-01-21      4
 1563        Hedley Gutierrez    2016-01-27      4
 1563        Hedley Gutierrez    2016-01-28      4
 1563        Hedley Gutierrez    2016-01-30      4
 1563        Hedley Gutierrez    2016-02-27      4
 1563        Hedley Gutierrez    2016-03-26      4
 1563        Hedley Gutierrez    2016-04-06      4
 1563        Hedley Gutierrez    2016-04-09      4
 1563        Hedley Gutierrez    2016-04-22      4
 1563        Hedley Gutierrez    2016-05-06      4
 1563        Hedley Gutierrez    2016-05-26      4
 1563        Hedley Gutierrez    2016-06-02      4
 1563        Hedley Gutierrez    2016-07-14      4
 1563        Hedley Gutierrez    2016-07-29      4
 1563        Hedley Gutierrez    2016-08-09      7
 1563        Hedley Gutierrez    2016-09-01      4
 1563        Hedley Gutierrez    2016-09-23      4
 1563        Hedley Gutierrez    2016-12-07      4
 1636        Kiara Lowery        2016-01-12      4
 2917        Cynthia Carr        2016-06-21      4
 2917        Cynthia Carr        2016-10-21      4
 3219        Alan Monroe         2016-01-02      4
 3219        Alan Monroe         016-02-27       4
 3219        Alan Monroe         2016-09-01      5
 4288        Natalie Mitchell    2016-03-19      4

如何让结果只显示ClientID和ClientName一次,结果是这样的？

 ClientID   ClientName            VisitDate      Number of Visits
 75         Kay Taylor            2016-06-07     4
 372         Moses Mcgowan       2016-09-03      4
 422         Raven Mckay         2016-03-11      4
                                 2016-06-14      4
 679         Ulysses Booker      2016-01-09      4
 696         Timon Turner        2016-07-06      4
 1063        Quyn Wall           2016-06-25      4
 1142        Garth Moran         2016-11-20      4
                                 2016-11-21      4
 1563        Hedley Gutierrez    2016-01-07      4
                                 2016-01-17      4
                                 2016-01-21      4
                                 2016-01-27      4
                                 2016-01-28      4
                                 2016-01-30      4
                                 2016-02-27      4
                                 2016-03-26      4
                                 2016-04-06      4
                                 2016-04-09      4
                                 2016-04-22      4
                                 2016-05-06      4
                                 2016-05-26      4
                                 2016-06-02      4
                                 2016-07-14      4
                                 2016-07-29      4
                                 2016-08-09      7
                                 2016-09-01      4
                                 2016-09-23      4
                                 2016-12-07      4
 1636        Kiara Lowery        2016-01-12      4
 2917        Cynthia Carr        2016-06-21      4
                                 2016-10-21      4
 3219        Alan Monroe         2016-01-02      4
 3219                            016-02-27       4
                                 2016-09-01      5
 4288        Natalie Mitchell    2016-03-19      4

Answer 1

实际上,你想要的不是删除重复项,而是不显示重复项.

为了做到这一点,你可以使用一个CASE语句,ROW_NUMBER()并显示在第1行的值并显示无论是NULL或''在ELSE分公司(其它行):

select 
   CASE
       WHEN ROW_NUMBER() OVER (PARTITION BY C.ClientID ORDER BY CAST(V.StartDate as date) ASC) = 1 
           THEN C.ClientID
       ELSE NULL
   END as ClientID,
   CASE 
       WHEN ROW_NUMBER() OVER (PARTITION BY C.ClientID ORDER BY CAST(V.StartDate as date) ASC) = 1 
           THEN C.FirstName + ' ' + C.LastName
       ELSE NULL 
   END as ClientName,
   CAST(V.StartDate as date) as VisitDate,
   count(*) as 'Number of Visits'
from
   Visit V
Inner Join Client C on
   V.ClientID = C.ClientID
group by 
   C.ClientID,
   C.FirstName + ' ' + C.LastName,
   CAST(V.StartDate as date)
having
   count(*) > 3
order by
   C.ClientID, 
   CAST(V.StartDate as date)