在 C++ 中使用 Linux 的控制台大小

Question

我正在尝试创建一个类似于moreLinux 的程序，但没有一些参数。主要思想是我需要从文本文件中输出信息，并在命令字符串中包含一些参数。所以我的主要论点是more -d fileName。

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我知道more输出 23 个带有文本的字符串，第 24 个是用户按下的space并获取另一个信息屏幕，但我需要考虑到用户可以更改控制台窗口的大小。

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我正在尝试使用图书馆#include <sys/ioctl.h>，但它说我不能使用这样的库。我究竟做错了什么？

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我的代码：

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#include <iostream>\n#include <fstream>\n#include <vector>\n#include <string>\n#include <sys/ioctl.h>\n\nvoid printRecord(struct winsize w, std::vector<std::string> lines);\n\nint main(int argc, char *argv[]) {\n    struct winsize w;\n    ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);\n    std::ifstream readRecord;\n    std::string more("more");\n    std::vector<std::string> lines;\n\n    std::cout << "argc: " << argc << std::endl;\n    for (int i = 0; i < argc; i++)\n    {\n        std::cout << "Argument: " << i << " = " << argv[i] << std::endl;\n    }\n    std::cout << std::endl << std::endl;\n\n    if (argv[1] == more)\n    {\n        std::string str;\n        //int n = atoi(argv[2]);\n        int numberPages=0;\n        readRecord.open(argv[2]);\n\n        while (!readRecord.eof())\n        {\n            getline(readRecord, str);\n            numberPages++;\n            lines.push_back(str);\n        }\n        if (0 == numberPages)\n        {\n            std::cout << "ERROR: The file is empty" << std::endl;\n            exit(-1);\n        }\n        if (w.ws_row > numberPages)\n        {\n            printRecord(struct winsize w, lines);\n        }\n        else\n        {\n            printRecord(struct winsize w, lines);\n        }\n    }\n\n    return 0;\n}\nvoid printRecord(struct winsize w,std::vector<std::string> lines)\n{\n    for (int i = 0; i < w.winsize::ws_row; i++)\n    {\n        std::cout << lines[i] << std::endl;\n    }\n}\n

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错误：

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#include <iostream>\n#include <fstream>\n#include <vector>\n#include <string>\n#include <sys/ioctl.h>\n\nvoid printRecord(struct winsize w, std::vector<std::string> lines);\n\nint main(int argc, char *argv[]) {\n    struct winsize w;\n    ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);\n    std::ifstream readRecord;\n    std::string more("more");\n    std::vector<std::string> lines;\n\n    std::cout << "argc: " << argc << std::endl;\n    for (int i = 0; i < argc; i++)\n    {\n        std::cout << "Argument: " << i << " = " << argv[i] << std::endl;\n    }\n    std::cout << std::endl << std::endl;\n\n    if (argv[1] == more)\n    {\n        std::string str;\n        //int n = atoi(argv[2]);\n        int numberPages=0;\n        readRecord.open(argv[2]);\n\n        while (!readRecord.eof())\n        {\n            getline(readRecord, str);\n            numberPages++;\n            lines.push_back(str);\n        }\n        if (0 == numberPages)\n        {\n            std::cout << "ERROR: The file is empty" << std::endl;\n            exit(-1);\n        }\n        if (w.ws_row > numberPages)\n        {\n            printRecord(struct winsize w, lines);\n        }\n        else\n        {\n            printRecord(struct winsize w, lines);\n        }\n    }\n\n    return 0;\n}\nvoid printRecord(struct winsize w,std::vector<std::string> lines)\n{\n    for (int i = 0; i < w.winsize::ws_row; i++)\n    {\n        std::cout << lines[i] << std::endl;\n    }\n}\n

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Answer 1

问题是你用过

#include <sys/ioct1.h>

并且有一个拼写错误：1而不是l。尝试使用：

#include <sys/ioctl.h>

反而