返回Bad Bad(WebApi)的错误列表

Tez*_*eld 4 c# asp.net-web-api2

如标题所示,如果“模型”不完整,我将尝试返回所有错误的自定义集合。

尽管积极地进行“ SO'ing / Google搜索”,但我还没有找到解决我的问题的解决方案。

我可以使用“ ModelState”,但是由于“自定义”,我想手动执行此操作。

代码如下:

API级别

// POST api/<controller>
[HttpPost]
[Route("")]
public async Task<IHttpActionResult> Post([FromBody]Order order)
{
    var modelResponse = new ModelResponse<Order>(order);
    if (order == null)
        return BadRequest("Unusable resource, object instance required.");

    //Check if all required properties contain values, if not, return response
    //with the details
    if (!modelResponse.IsModelValid())
        return this.PropertiesRequired(modelResponse.ModelErrors());

    try
    {
        await _orderService.AddAsync(order);
    }
    catch (System.Exception ex)
    {
        return InternalServerError();
    }
    finally
    {
        _orderService.Dispose();
    }

    return Ok("Order Successfully Processed.");
}
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需要的属性操作结果

public List<string> Messages { get; private set; }
public HttpRequestMessage Request { get; private set; }

public PropertiesRequiredActionResult(List<string> message, 
    HttpRequestMessage request)
{
    this.Messages = message;
    this.Request = request;
}
public Task<HttpResponseMessage> ExecuteAsync(CancellationToken cancellationToken)
{
    return Task.FromResult(Execute());
}

public HttpResponseMessage Execute()
{
    HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.BadRequest);
    response.Content = new ObjectContent()
        //new List<StringContent>(Messages); //Stuck here
    response.RequestMessage = Request;
    return response;
}
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根据自定义属性查找不完整的属性

private T _obj;

public ModelResponse(T obj)
{
    _obj = obj;
}

private Dictionary<string, object> GetPropertyAttributes(PropertyInfo property)
{
    Dictionary<string, object> attribs = new Dictionary<string, object>();
    // look for attributes that takes one constructor argument
    foreach (CustomAttributeData attribData in property.GetCustomAttributesData())
    {

        if (attribData.ConstructorArguments.Count == 1)
        {
            string typeName = attribData.Constructor.DeclaringType.Name;
            if (typeName.EndsWith("Attribute")) typeName = typeName.Substring(0, typeName.Length - 9);
            attribs[typeName] = attribData.ConstructorArguments[0].Value;
        }

    }
    return attribs;
}
private IEnumerable<PropertyInfo> GetProperties()
{
    var props = typeof(T).GetProperties().Where(
            prop => Attribute.IsDefined(prop, typeof(APIAttribute)));

    return props;
}
public bool IsModelValid()
{
    var props = GetProperties();
    return props.Any(p => p != null);
}
public List<string> ModelErrors()
{
        List<string> errors = new List<string>();
        foreach (var p in GetProperties())
        {

            object propertyValue = _obj.GetType()
                .GetProperty(p.Name).GetValue(_obj, null);

            if (propertyValue == null)
            {
                errors.Add(p.Name + " - " + GetPropertyAttributes(p).FirstOrDefault());
            }
        }
        return errors;
}
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属性样本

/// <summary>
/// The date and time when the order was created.
/// </summary>
[API(Required = "Order Created At Required")]
public DateTime Order_Created_At { get; set; }
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因此,忽略后面的两个代码片段,更多的是提供完整的过程概述。我完全理解有一些“开箱即用”的技术,但我确实喜欢精心设计自己的实现。

到目前为止,是否可以使用“ BadRequest”返回错误列表?

非常感激。

Fel*_* Av 5

您可能正在寻找使用此方法的方法:

BadRequestObjectResult BadRequest(ModelStateDictionary modelState)
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它的用法是这样的,示例来自SO中的另一个问题

if (!ModelState.IsValid)
     return BadRequest(ModelState);
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根据模型错误,您将获得以下结果:

{
   Message: "The request is invalid."
   ModelState: {
       model.PropertyA: [
            "The PropertyA field is required."
       ],
       model.PropertyB: [
             "The PropertyB field is required."
       ]
   }
}
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希望能帮助到你


Nko*_*osi 2

在您的自定义实现中,IHttpActionResult使用请求创建响应并传递模型和状态代码。

public List<string> Messages { get; private set; }
public HttpRequestMessage Request { get; private set; }

public HttpResponseMessage Execute() {
    var response = Request.CreateResponse(HttpStatusCode.BadRequest, Messages);
    return response;
}
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