如何使用Glide在imageview上获取URI

Question

我正在使用“ Glide”将图像从服务器加载到ImageView。我想知道是否有可能从imageview本身提取该URI。

ImageView contentImage = (ImageView) findViewById(R.id.contentImage);

........

Glide.with(getApplicationContext()).load(contentImageUrl)
.crossFade()
.diskCacheStrategy(DiskCacheStrategy.ALL)
.into(contentImage);  

我的目的是在Imageview中共享图像。如何使用Glide在imageview上获取URI？

Uri uri = ??????????????

Intent shareIntent = new Intent();
shareIntent.setAction(Intent.ACTION_SEND);
shareIntent.setType("image/*");
shareIntent.putExtra(Intent.EXTRA_STREAM, uri);
shareIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
startActivity(Intent.createChooser(shareIntent, "Share Image"));

Answer 1

使Uri将您的Glide实现更改为：

Bitmap bitmap;

 Glide.with(getApplicationContext())
                .load(contentImageUrl)
                .asBitmap()
                .into(new SimpleTarget<Bitmap>() {
                    @Override
                    public void onResourceReady(Bitmap resource, GlideAnimation<? super Bitmap> glideAnimation) {
                        // you can do something with loaded bitmap here
                        contentImage.setImageBitmap(resource);
                        bitmap= resource;
                    }
                });

现在调用方法；

    //get URI from bitmap
   Uri uri = getImageUri(getApplicationContext(),bitmap);

在getImageUri功能上：

public Uri getImageUri(Context inContext, Bitmap inImage) {
  ByteArrayOutputStream bytes = new ByteArrayOutputStream();
  inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
  String path = MediaStore.Images.Media.insertImage(MainActivity.this.getContentResolver(), inImage, UUID.randomUUID().toString() + ".png", "drawing");
  return Uri.parse(path);
} 

您需要在清单中添加权限：

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

同样对于运行时权限：Api> = 23

ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE}, 1);