如何交错numpy.ndarrays？

Question

我目前正在寻找可以交错2 numpy.ndarray的方法.这样的

>>> a = np.random.rand(5,5)
>>> print a
[[ 0.83367208  0.29507876  0.41849799  0.58342521  0.81810562]
 [ 0.31363351  0.69468009  0.14960363  0.7685722   0.56240711]
 [ 0.49368821  0.46409791  0.09042236  0.68706312  0.98430387]
 [ 0.21816242  0.87907115  0.49534121  0.60453302  0.75152033]
 [ 0.10510938  0.55387841  0.37992348  0.6754701   0.27095986]]
>>> b = np.random.rand(5,5)
>>> print b
[[ 0.52237011  0.75242666  0.39895415  0.66519185  0.87043142]
 [ 0.08624797  0.66193953  0.80640822  0.95403594  0.33977566]
 [ 0.13789573  0.84868366  0.09734757  0.06010175  0.48043968]
 [ 0.28871551  0.62186888  0.44603741  0.3351644   0.6417847 ]
 [ 0.85745394  0.93179792  0.62535765  0.96625077  0.86880908]]
>>> 

print c shoule将每行交错两个矩阵

[ 0.83367208   0.52237011  0.29507876 0.75242666 0.41849799 0.39895415 0.58342521 0.66519185 0.81810562 0.87043142]

我总共有三个应该是交错的,但我想一次做两个会更容易.

但是我如何轻松地做到这一点..我读了一些使用数组的方法,但我不确定用ndarrays做什么？

Answer 1

沿着第三轴堆叠,np.dstack然后重新形成2D-

np.dstack((a,b)).reshape(a.shape[0],-1)

使用三个阵列或更多数量的阵列,只需添加其中.因此,对于三个数组,使用:np.dstack((a,b,c))并重塑c为第三个数组.

样品运行 -

In [99]: a
Out[99]: 
array([[8, 4, 0, 5, 6],
       [0, 2, 3, 0, 6],
       [4, 4, 0, 6, 5],
       [7, 5, 0, 7, 0],
       [6, 7, 4, 7, 2]])

In [100]: b
Out[100]: 
array([[3, 5, 8, 6, 5],
       [5, 6, 8, 8, 4],
       [8, 3, 3, 3, 5],
       [2, 1, 1, 1, 3],
       [5, 7, 7, 5, 7]])

In [101]: np.dstack((a,b)).reshape(a.shape[0],-1)
Out[101]: 
array([[8, 3, 4, 5, 0, 8, 5, 6, 6, 5],
       [0, 5, 2, 6, 3, 8, 0, 8, 6, 4],
       [4, 8, 4, 3, 0, 3, 6, 3, 5, 5],
       [7, 2, 5, 1, 0, 1, 7, 1, 0, 3],
       [6, 5, 7, 7, 4, 7, 7, 5, 2, 7]])