在Python中,是否有一种紧凑的方法在符合条件的列表中打印这些变量的名称？

Question

我正在为脚本的调试模式编写一些打印输出.是否有一种紧凑的方法在符合条件的列表中打印这些变量的名称？

specification_aw3 = 43534
specification_hg7 = 75445
specification_rt5 = 0
specification_nj8 = 5778
specification_lo4 = 34
specification_ee2 = 8785
specification_ma2 = 67
specification_pw1 = 1234
specification_mu6 = 0
specification_xu8 = 12465

specifications = [
    specification_aw3,
    specification_hg7,
    specification_rt5,
    specification_nj8,
    specification_lo4,
    specification_ee2,
    specification_ma2,
    specification_pw1,
    specification_mu6,
    specification_xu8
]

if any(specification == 0 for specification in specifications):
    # magic code to print variables' names
    # e.g. "variables equal to 0: \"specification_rt5\", \"specification_mu6\"

正如9000所暗示的那样,不言而喻,定义字典对于我在此定义的最小工作示例来说是一种理性的方法.请假设这对于现有代码项目来说不是一个可行的选项,而且我正在寻找一个快速,紧凑(似乎难看)的代码,仅用于调试.

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编辑:类似于我想要的东西的插图

所以这是我正在寻找的开始:

print("specifications equal to zero:")
callers_local_objects = inspect.currentframe().f_back.f_locals.items()
for specification in [specification for specification in specifications if specification == 0]:
    print([object_name for object_name, object_instance in callers_local_objects if object_instance is specification][0])

基本上,是否有一种紧凑的方式来做这样的事情？

Answer 1

我建议你使用dict而不是一堆变量:

specification = {
  'aw3': 0,
  'foo': 1,
  'bar': 1.23,
  # etc
} 

您可以按名称访问specification['aw3'].

然后你可以找到值为的名称0:

zeroed = [name for (name, value) in specification.items() if value == 0]