将数据帧中的字符串行替换为其他数据帧panda中的相应字

Question

我有一个有1列的df

     List
 0   What are you trying to achieve
 1   What is your purpose right here
 2   When students don’t have a proper foundation
 3   I am going to DESCRIBE a sunset

我有其他数据帧df2

它有2列

    original       correct
0     are          were
1     sunset       sunrise
2     I            we
3     right        correct
4     is           was

我想在我的df中替换这样的单词,这些单词出现在original我的df2列中,并替换为correct列中的相应单词.并将新字符串存储在其他数据帧中df_new

是否可以不使用循环和迭代,只使用普通的熊猫概念？

即我df_new应该包含.

     List
 0   What were you trying to achieve
 1   What was your purpose correct here
 2   When students don’t have a proper foundation
 3   we am going to DESCRIBE a sunrise

这也只是一个测试示例,我可能会拥有df数百万行字符串,所以我的df2,我能继续进行的最有效的解决方案路径是什么？

Answer 1

许多可能的解决方案之一：

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In [371]: boundary = r'\\b'\n     ...:\n     ...: df.List.replace((boundary + df2.orignal + boundary).values.tolist(),\n     ...:                 df2.correct.values.tolist(),\n     ...:                 regex=True)\n     ...:\nOut[371]:\n0                  What were you trying to achieve\n1               What was your purpose correct here\n2     When students don\xe2\x80\x99t have a proper foundation\n3                we am going to DESCRIBE a sunrise\nName: List, dtype: object\n

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