Mar*_*mes 3 html php select onchange dropdown
我尝试使用以下代码执行的操作是从下拉菜单中调用PHP函数。
有一种干净的方法吗？
码：
<html>
<head>
</head>
<body>
<?php
function OnSelectionChange() {
echo("OK IT WORKS");
}
?>
<section>
<select onchange="OnSelectionChange()">
<option value='' disabled selected>Assign Driver</option>
<option value='4353'>Steve Jobs</option>
<option value='3333'>Ian Wright</option>
<option value='66666'>Mark James</option>
</select>
</section>
</body>
</html>
小智 6
您可以使用php而不使用JavaScript从下拉列表中获取选定的值。
<html>
<head>
<title>Country</title>
</head>
<body>
<form>
Select Your Country
<select name="country" onchange="this.form.submit()">
<option value="" disabled selected>--select--</option>
<option value="india">India</option>
<option value="us">Us</option>
<option value="europe">Europe</option>
</select>
</form>
<?php
if(isset($_GET["country"])){
$country=$_GET["country"];
echo "select country is => ".$country;
}
?>
</body>
</html>使用jquery的简单ajax
索引页
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('#myDropDown').change(function(){
//Selected value
var inputValue = $(this).val();
alert("value in js "+inputValue);
//Ajax for calling php function
$.post('submit.php', { dropdownValue: inputValue }, function(data){
alert('ajax completed. Response: '+data);
//do after submission operation in DOM
});
});
});
</script>
</head>
<body>
<select id="myDropDown">
<option value='' disabled selected>Assign Driver</option>
<option value='4353'>Steve Jobs</option>
<option value='3333'>Ian Wright</option>
<option value='66666'>Mark James</option>
</select>
</body>
</html>
在提交.php
<?php
function processDrpdown($selectedVal) {
echo "Selected value in php ".$selectedVal;
}
if ($_POST['dropdownValue']){
//call the function or execute the code
processDrpdown($_POST['dropdownValue']);
}
对于简单的 js ajax 使用XMLHttpRequest