Jos*_*h K 11 java grails groovy
我有ip地址和一个掩码,如10.1.1.1/32.我想检查是否10.1.1.1在该范围内.是否有可以执行此操作的库或实用程序,或者我是否需要自己编写内容?
Joh*_*ica 28
首先,您需要将IP地址转换为平面int,这将更容易使用:
String s = "10.1.1.99";
Inet4Address a = (Inet4Address) InetAddress.getByName(s);
byte[] b = a.getAddress();
int i = ((b[0] & 0xFF) << 24) |
((b[1] & 0xFF) << 16) |
((b[2] & 0xFF) << 8) |
((b[3] & 0xFF) << 0);
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一旦将IP地址作为普通ints,就可以执行一些算术来执行检查:
int subnet = 0x0A010100; // 10.1.1.0/24
int bits = 24;
int ip = 0x0A010199; // 10.1.1.99
// Create bitmask to clear out irrelevant bits. For 10.1.1.0/24 this is
// 0xFFFFFF00 -- the first 24 bits are 1's, the last 8 are 0's.
//
// -1 == 0xFFFFFFFF
// 32 - bits == 8
// -1 << 8 == 0xFFFFFF00
mask = -1 << (32 - bits)
if ((subnet & mask) == (ip & mask)) {
// IP address is in the subnet.
}
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