递归获取类的所有属性C＃

Question

我有一堂课，看起来像

public class Employee
{
    public string FirstName { get; set; };
    public string LastName { get; set; }; 
    public Address Address { get; set; };  
}

public class Address 
{
    public string HouseNo { get; set; };
    public string StreetNo { get; set; }; 
    public SomeClass someclass { get; set; }; 
}

public class SomeClass 
{
    public string A{ get; set; };
    public string B{ get; set; }; 
}

我想出了一种使用反射来查找类的原始属性的方法，例如字符串，int bool等

但是我还需要找出像ex这样的类中所有复杂类型的列表。带有Class Employee的Address类和Address内的SomeClass类

Answer 1

如果您已经知道如何使用反射，则应该很容易：

private List<Type> alreadyVisitedTypes = new List<Type>(); // to avoid infinite recursion
public static void PrintAllTypes(Type currentType, string prefix)
{
    if (alreadyVisitedTypes.Contains(currentType)) return;
    alreadyVisitedTypes.Add(currentType);
    foreach (PropertyInfo pi in currentType.GetProperties())
    {
        Console.WriteLine($"{prefix} {pi.PropertyType.Name} {pi.Name}");
        if (!pi.PropertyType.IsPrimitive) PrintAllTypes(pi.PropertyType, prefix + "  ");
    }
}

像这样的电话

PrintAllTypes(typeof(Employee), string.Empty);

会导致：

String FirstName
  Char Chars
  Int32 Length
String LastName
Address Address
  String HouseNo
  String StreetNo
  SomeClass someclass
     String A
     String B