BigQuery中的HAVERSINE距离?

Fel*_*ffa 8 geo google-bigquery

我正在寻找一种在BigQuery中获取HAVERSINE()的方法.例如,如何让最近的气象站到任意点?

Ell*_*ard 12

使用标准SQL,您可以定义一个SQL函数来封装逻辑.例如,

#standardSQL
CREATE TEMP FUNCTION RADIANS(x FLOAT64) AS (
  ACOS(-1) * x / 180
);
CREATE TEMP FUNCTION RADIANS_TO_KM(x FLOAT64) AS (
  111.045 * 180 * x / ACOS(-1)
);
CREATE TEMP FUNCTION HAVERSINE(lat1 FLOAT64, long1 FLOAT64,
                               lat2 FLOAT64, long2 FLOAT64) AS (
  RADIANS_TO_KM(
    ACOS(COS(RADIANS(lat1)) * COS(RADIANS(lat2)) *
         COS(RADIANS(long1) - RADIANS(long2)) +
         SIN(RADIANS(lat1)) * SIN(RADIANS(lat2))))
);

SELECT
  lat,
  lon,
  name,
  HAVERSINE(40.73943, -73.99585, lat, lon) *1000 AS haversine_distance
  , ST_DISTANCE(
      ST_GEOGPOINT(-73.99585, 40.73943)
      , ST_GEOGPOINT(lon,lat)) bqgis_distance
FROM `bigquery-public-data.noaa_gsod.stations`
WHERE lat IS NOT NULL AND lon IS NOT NULL
ORDER BY 1 DESC
LIMIT 4;
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Fel*_*ffa 5

2018更新:BigQuery现在支持本机地理功能。

ST_DISTANCE:返回两个非空GEOGRAPHY之间的最短距离(以米为单位)。

纽约到西雅图的距离:

#standardSQL
WITH geopoints AS (
  SELECT ST_GEOGPOINT(lon,lat) p, name, state
  FROM `bigquery-public-data.noaa_gsod.stations`  
)

SELECT ST_DISTANCE(
  (SELECT p FROM geopoints WHERE name='PORT AUTH DOWNTN MANHATTAN WA'),
  (SELECT p FROM geopoints WHERE name='SEATTLE')
)

3866381.55
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旧版SQL解决方案(标准待定):

SELECT lat, lon, name,
  (111.045 * DEGREES(ACOS(COS(RADIANS(40.73943)) * COS(RADIANS(lat)) * COS(RADIANS(-73.99585) - RADIANS(lon)) + SIN(RADIANS(40.73943)) * SIN(RADIANS(lat))))) AS distance
FROM [bigquery-public-data:noaa_gsod.stations]
HAVING distance>0
ORDER BY distance
LIMIT 4
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在此处输入图片说明

(基于http://www.plumislandmedia.net/mysql/haversine-mysql-nearest-loc/