在laravel中使用自定义软删除列

Question

我知道如何在laravel模型中使用Soft Deleting功能.像这样 :

class Flight extends Model
{
    use SoftDeletes;

    protected $dates = ['deleted_at'];
}

但我想用命名的自定义柱sender_deleted_at为特征,其中像所有的相关方法forceDelete,restore,withTrashed和等工作,基于该列.

我写了这个问题但是我找不到正确的答案.

我正在使用Laravel 5.3.

Answer 1

SoftDeletes trait使用此代码"删除"一行:

protected function runSoftDelete() {
        $query = $this->newQueryWithoutScopes()->where($this->getKeyName(), $this->getKey());
        $this->{$this->getDeletedAtColumn()} = $time = $this->freshTimestamp();
        $query->update([$this->getDeletedAtColumn() => $this->fromDateTime($time)]);
}

身体getDeletedAtColumn()是:

public function getDeletedAtColumn() {
    return defined('static::DELETED_AT') ? static::DELETED_AT : 'deleted_at';
}

因此你可以这样做:

class Flight extends Model
{
    use SoftDeletes;    
    protected $dates = ['my_deleted_at'];
    const DELETED_AT = 'my_deleted_at';
}

Answer 2

简答:只需const DELETED_AT在模型中声明一个并给它一个你想要使用的列名.

<?php

namespace App;

use Illuminate\Database\Eloquent\SoftDeletes;
use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;

class User extends Authenticatable
{
    use SoftDeletes;

    use Notifiable;

    const DELETED_AT = 'deletedAt';
}

说明:如果你看一下方法好getDeletedAtColumn于trait Illuminate\Database\Eloquent\SoftDeletes

/**
 * Get the name of the "deleted at" column.
 *
 * @return string
 */
public function getDeletedAtColumn()
{
    return defined('static::DELETED_AT') ? static::DELETED_AT : 'deleted_at';
}

它实际上检查你是否DELETED_AT在实现类中声明了一个常量名,而不是获取该值,如果你还没有简单地deleted_at用作软删除列.