request.form["name"]例如,当我输入从POST提交的表单中检索名称时,我是否还要编写一个看起来像的单独分支request.form.get["name"]?如果我想支持这两种方法,需要为所有POST和所有GET请求编写单独的语句吗?
@app.route("/register", methods=["GET", "POST"])
def register():
"""Register user."""
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我的问题与使用python和Flask获取请求变量的值相关.
jbn*_*dlr 35
您可以区分使用request.method此处概述的实际方法:http://flask.pocoo.org/docs/0.10/quickstart/#http-methods
我假设你想:
GET方法触发路径时渲染模板POST因此,您的案例类似于文档中描述的案例(上面链接):
import flask
app = flask.Flask('your_flask_env')
@app.route('/register', methods=['GET', 'POST'])
def register():
if flask.request.method == 'POST':
username = flask.request.values.get('user') # Your form's
password = flask.request.values.get('pass') # input names
your_register_routine(username, password)
else:
# You probably don't have args at this route with GET
# method, but if you do, you can access them like so:
yourarg = flask.request.args.get('argname')
your_register_template_rendering(yourarg)
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小智 7
在此示例中,您可以轻松找到使用 POST、GET 方法的方法,并使用相同的方法添加其他 Curd 操作。
#libraries to include
import os
from flask import request, jsonify
from app import app, mongo
import logger
ROOT_PATH = os.environ.get('ROOT_PATH')
@app.route('/get/questions/', methods=['GET', 'POST','DELETE', 'PATCH'])
def question():
# request.args is to get urls arguments
if request.method == 'GET':
start = request.args.get('start', default=0, type=int)
limit_url = request.args.get('limit', default=20, type=int)
questions = mongo.db.questions.find().limit(limit_url).skip(start);
data = [doc for doc in questions]
return jsonify(isError= False,
message= "Success",
statusCode= 200,
data= data), 200
# request.form to get form parameter
if request.method == 'POST':
average_time = request.form.get('average_time')
choices = request.form.get('choices')
created_by = request.form.get('created_by')
difficulty_level = request.form.get('difficulty_level')
question = request.form.get('question')
topics = request.form.get('topics')
##Do something like insert in DB or Render somewhere etc. it's up to you....... :)
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