Mic*_*ael 6 javascript immutable.js
我在React Native应用程序中使用Redutable使用Immutable.js.
元数据(例如查找表)从服务器获取,并作为Immutable.Map在应用程序中本地保存.查找值的键是整数(db中的主键).
当我获取数据时,所有整数键都被强制转换为字符串.这是js对象的正常行为.因此,当创建查找映射时,键将是字符串.
例:
let colors = Immutable.Map({
'10': 'yellow',
'20': 'pink',
..
})
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引用查找值的对象将引用存储为数字,如下所示:
let michael = Immutable.Map({
name: 'Michael',
colorId: 10
})
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由于Immutable.js不会将数字键强制转换为字符串,因此无法执行此操作:
let color = colors.get(michael.get('colorId'))
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以上内容与:
let color = colors.get(10)
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这不起作用,因为id是一个字符串.这可行:
let color = colors.get('10')
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我通常使用Immutable.List来存储从服务器获取的数据集.要获得一个项目,我使用find().但是经常访问小的查找表(基本上是应用程序元数据)并且需要快速.
你是如何解决这个问题的?以下是一些需要考虑的选择:
let color = colors.get(michael.get('colorId') + '')
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缺点:
优点:
缺点:
优点:
缺点:
let colors = new Immutable.Map()
.set(10, 'yellow')
.set(20, 'pink')
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优点:
缺点:
来自简单性能测试的有趣数据.
Immutable.Map与数字键:185毫秒
使用find()的Immutable.List:972 ms
带有强制密钥的普通JS对象:8毫秒
使用find()的普通JS数组:127毫秒
因为我正在使用React Native,如果我想达到60 fps,我总是要注意16 ms的限制.基准值似乎不是线性的.仅使用100次查找运行测试需要1 ms的Map和2 ms的List.那太贵了.
我在基准测试中做错了吗?否则我想我现在必须离开Immutable.js :(
let Immutable = require('immutable');
let mapTest = Immutable.Map()
.set(1, Immutable.Map({value: 'one'}))
.set(2, Immutable.Map({value: 'two'}))
.set(3, Immutable.Map({value: 'three'}))
.set(4, Immutable.Map({value: 'four'}))
.set(5, Immutable.Map({value: 'five'}))
.set(6, Immutable.Map({value: 'six'}))
.set(7, Immutable.Map({value: 'seven'}))
.set(8, Immutable.Map({value: 'eight'}))
.set(9, Immutable.Map({value: 'nine'}))
.set(10, Immutable.Map({value: 'ten'}));
let listTest = Immutable.fromJS([
{key: 1, value: 'one'},
{key: 2, value: 'two'},
{key: 3, value: 'three'},
{key: 4, value: 'four'},
{key: 5, value: 'five'},
{key: 6, value: 'six'},
{key: 7, value: 'seven'},
{key: 8, value: 'eight'},
{key: 9, value: 'nine'},
{key: 10, value: 'ten'}
])
let objTest = {
1: {value: 'one'},
2: {value: 'two'},
3: {value: 'three'},
4: {value: 'four'},
5: {value: 'five'},
6: {value: 'six'},
7: {value: 'seven'},
8: {value: 'eight'},
9: {value: 'nine'},
10: {value: 'ten'}
};
let arrayTest = [
{key: 1, value: 'one'},
{key: 2, value: 'two'},
{key: 3, value: 'three'},
{key: 4, value: 'four'},
{key: 5, value: 'five'},
{key: 6, value: 'six'},
{key: 7, value: 'seven'},
{key: 8, value: 'eight'},
{key: 9, value: 'nine'},
{key: 10, value: 'ten'}
];
const runs = 1e6;
let i;
let key;
let hrStart;
console.log(' ')
console.log('mapTest -----------------------------')
key = 1;
hrstart = process.hrtime();
for(i=0; i<runs; i++) {
let result = mapTest.getIn([key, 'value'] )
key = (key >= 10) ? 1 : key + 1;
}
hrend = process.hrtime(hrstart);
console.info("Execution time (hr): %dms", hrend[0] * 1000 + hrend[1]/1000000);
console.log(' ')
console.log('listTest -----------------------------')
key = 1;
hrstart = process.hrtime();
for(i=0; i<runs; i++) {
let result = listTest
.find(item => item.get('key') === key)
.get('value');
key = (key >= 10) ? 1 : key + 1;
}
hrend = process.hrtime(hrstart);
console.info("Execution time (hr): %dms", hrend[0] * 1000 + hrend[1]/1000000);
console.log(' ')
console.log('arrayTest -----------------------------')
key = 1;
hrstart = process.hrtime();
for(i=0; i<runs; i++) {
let result = arrayTest
.find(item => item.key === key)
.value
key = (key >= 10) ? 1 : key + 1;
}
hrend = process.hrtime(hrstart);
console.info("Execution time (hr): %dms", hrend[0] * 1000 + hrend[1]/1000000);
console.log(' ')
console.log('objTest -----------------------------')
key = 1;
hrstart = process.hrtime();
for(i=0; i<runs; i++) {
let result = objTest[key].value
key = (key >= 10) ? 1 : key + 1;
}
hrend = process.hrtime(hrstart);
console.info("Execution time (hr): %dms", hrend[0] * 1000 + hrend[1]/1000000);
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