如何获取给定日期之间每天的行数？

Question

我有以下格式的表格.当我在2008-10-12和2008-10-13之间给出日期时,我需要mysql查询来获取每天的行数

 Name | KW     | KV   | I    | Date                |
------+--------+------+------+---------------------+
 UPS1 | 353.50 | NULL | NULL | 2008-10-12 00:54:36 |
 UPS1 | 352.50 | NULL | NULL | 2008-10-12 01:54:36 |
 UPS1 | 351.90 | NULL | NULL | 2008-10-12 02:54:36 |
 UPS1 | 351.60 | NULL | NULL | 2008-10-12 03:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 04:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 05:54:36 |
 UPS1 | 351.90 | NULL | NULL | 2008-10-12 06:54:36 |
 UPS1 | 352.50 | NULL | NULL | 2008-10-12 07:54:36 |
 UPS1 | 352.50 | NULL | NULL | 2008-10-12 08:54:36 |
 UPS1 | 353.20 | NULL | NULL | 2008-10-12 09:54:36 |
 UPS1 | 353.50 | NULL | NULL | 2008-10-12 10:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 11:54:36 |
 UPS1 | 352.50 | NULL | NULL | 2008-10-12 12:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 13:54:36 |
 UPS1 | 353.20 | NULL | NULL | 2008-10-12 14:54:36 |
 UPS1 | 353.50 | NULL | NULL | 2008-10-12 15:54:36 |
 UPS1 | 352.90 | NULL | NULL | 2008-10-12 16:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 17:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 18:54:36 |
 UPS1 | 352.90 | NULL | NULL | 2008-10-12 19:54:36 |
 UPS1 | 352.20 | NULL | NULL | 2008-10-12 20:54:36 |
 UPS1 | 352.50 | NULL | NULL | 2008-10-12 21:54:36 |
 UPS1 | 352.90 | NULL | NULL | 2008-10-12 22:54:36 |
 UPS1 | 353.20 | NULL | NULL | 2008-10-12 23:54:36 |
 UPS1 | 355.80 | NULL | NULL | 2008-10-13 00:54:36 |
 UPS1 | 358.40 | NULL | NULL | 2008-10-13 01:54:36 |
 UPS1 | 358.00 | NULL | NULL | 2008-10-13 02:54:36 |
 UPS1 | 359.00 | NULL | NULL | 2008-10-13 03:54:36 |
 UPS1 | 357.70 | NULL | NULL | 2008-10-13 04:54:36 |
 UPS1 | 357.40 | NULL | NULL | 2008-10-13 05:54:36 |
 UPS1 | 357.40 | NULL | NULL | 2008-10-13 06:54:36 |
 UPS1 | 359.00 | NULL | NULL | 2008-10-13 07:54:36 |
 UPS1 | 357.10 | NULL | NULL | 2008-10-13 08:54:36 |
 UPS1 | 359.00 | NULL | NULL | 2008-10-13 09:54:36 |
 UPS1 | 357.70 | NULL | NULL | 2008-10-13 10:54:36 |
 UPS1 | 357.40 | NULL | NULL | 2008-10-13 11:54:36 |
 UPS1 | 357.40 | NULL | NULL | 2008-10-13 12:54:36 |
 UPS1 | 359.00 | NULL | NULL | 2008-10-13 13:54:36 |
 UPS1 | 357.10 | NULL | NULL | 2008-10-13 14:54:36 |
 UPS1 | 358.00 | NULL | NULL | 2008-10-13 15:54:36 |
 UPS1 | 359.30 | NULL | NULL | 2008-10-13 16:54:36 |
 UPS1 | 357.10 | NULL | NULL | 2008-10-13 17:54:36 |
 UPS1 | 358.40 | NULL | NULL | 2008-10-13 18:54:36 |
 UPS1 | 357.70 | NULL | NULL | 2008-10-13 19:54:36 |
 UPS1 | 359.00 | NULL | NULL | 2008-10-13 20:54:36 |
 UPS1 | 358.70 | NULL | NULL | 2008-10-13 21:54:36 |
 UPS1 | 358.70 | NULL | NULL | 2008-10-13 22:54:36 |
 UPS1 | 358.40 | NULL | NULL | 2008-10-13 23:54:36 |

Answer 1

我更改了查询,以便Date列大小写完全匹配查询结果中的内容.

select Date, count(Date)
from TABLE
where Date >= '2008-10-12' and Date <= '2008-10-13'
group by Date

您需要在from子句中更改TABLE,但其他所有内容对于您的表都应该是正确的.

编辑:

我有一个类似结构的表,我更改了一个名为'Date'的日期列.以下对我有用.

mysql> select Date, count(Date) 
    from calendar_items 
    where date between '2008-12-12' and '2008-12-13' 
    group by Date;

+------------+-------------+
| Date       | count(Date) |
+------------+-------------+
| 2008-12-12 |          14 | 
| 2008-12-13 |           6 | 
+------------+-------------+
2 rows in set (0.00 sec)

mysql>