在一行中计算一个确切的字符 - cmd

Question

我想编写一个批处理文件来计算文本文件每一行中特定字符的出现次数。

例如，\字符串中的计数为"aa\bb\cc\dd\"4。

在find与findstr线这是只显示号码包含的确切性质。

Answer 1

这是一种方法：

 @echo off
:checkCountOf string countOf [rtnrVar]
:: checks count of a substring  in a string 
setlocal EnableDelayedExpansion
set "string=aa"

set "string=%~1"
set "checkCountOf=%~2"

if "%~1" equ "" (
    if "%~3" neq "" (
        endlocal & (
           echo 0
           set "%~3=0"
           exit /b 0
        )
    ) else (
        endlocal & (
           echo 0
           exit /b 0
        )
)


)

if "!checkCountOf!" equ "$" (
    set "string=#%string%#"
    set "string=!string:%checkCountOf%%checkCountOf%=#%checkCountOf%#%checkCountOf%#!"
) else (
    set "string=$%string%$"
    set "string=!string:%checkCountOf%%checkCountOf%=$%checkCountOf%$%checkCountOf%$!"
)


set LF=^


rem ** Two empty lines are required
set /a counter=0


for %%L in ("!LF!") DO (
    for /f "delims=" %%R in ("!checkCountOf!") do ( 
        set "var=!string:%%~R%%~R=%%~L!"
        set "var=!var:%%~R=%%~L!"

        for /f "tokens=* delims=" %%# in ("!var!") do (
            set /a counter=counter+1
        )
    )
)

if !counter! gtr 0 (
    set /a counter=counter-1
)

if "%~3" neq "" (
    endlocal & (
       echo %counter%
       set "%~3=%counter%"
    )
) else (
    endlocal & (
       echo %counter%
    )
)

你可以这样称呼它：

call ::checkCountOf "/aa/b/c/" "/" slashes
echo %slashes%
exit /b %errorlevel% 

不适用于某些特殊字符（"、~和!）

您还可以使用替换和:strlen 函数