我正在从终端接受问题并通过对话框发送回复,但我的程序只接受第一个输入并重复。
例如,当我运行我的脚本时,输出可能是这样的:
[Eliza]: Hi, I'm a psychotherapist. What is your name?
user Input: hello my name is adam.
[Eliza]: hello adam, how are you?
[Eliza]: your name is adam
[Eliza]: your name is adam
[Eliza]: your name is adam
[Eliza]: your name is adam
[Eliza]: your name is adam
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它无休止地重复。
我不知道我哪里做错了。如何让我的程序从键盘读取下一行?
sub hello {
print "[Eliza]: Hi, I'm a psychotherapist. What is your name? \n";
}
sub getPatientName {
my ($reply) = @_;
my @responses = ( "my name is", "i'm", "i am", "my name's" );
foreach my $response ( @responses ) {
if ( lc($reply) =~ /$response/ ) {
return "$'";
}
}
return lc($reply);
}
sub makeQuestion {
my ($patient) = @_;
my %reflections = (
"am" => "are",
"was" => "were",
"i" => "you",
"i'd" => "you would",
"i've" => "you have",
"i'll" => "you will",
"my" => "your",
"are" => "am",
"you've"=> "I have",
"you'll"=> "I will",
"your" => "my",
"yours" => "mine",
"you" => "me",
"me" => "you"
);
if ( $count == 0 ) {
$patientName = getPatientName($patient);
$count += 1;
print "Hello $patientName , How are you? \n";
}
my @toBes = keys %reflections;
foreach my $toBe (@toBes) {
if ($patient =~/$toBe/) {
$patient=~ s/$toBe/$reflections{$toBe}/i;
print "$patient? \n";
}
}
}
sub eliza {
hello();
my $answer = <STDIN>;
while ($answer) {
chomp $answer;
#remove . ! ;
$answer =~ s/[.!,;]/ /;
makeQuestion($answer);
}
}
eliza();
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您的while循环从不读取输入。在$answer得到了STDIN循环之前大概有一个字符串,其值在真实的while条件。循环中的正则表达式不能改变这一点。
因此,不仅没有新输入分配给$answer,而且在第一次迭代之后循环中没有任何变化。所以它永远运行,打印基于相同的问题$answer。
你需要
while (my $answer = <STDIN>) {
chomp $answer;
# ...
}
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反而。
每次while (...)评估的条件时,都会通过读取新输入<STDIN>并将其分配给$answer。然后每个新问题都使用新的$answer. 请注意如何在while条件内声明变量,使其仅存在于循环体中(以及声明后的条件中)。这是将其范围限制在循环内需要的地方的好方法。
该文件句柄读<...>返回undef时,它得到EOF(或错误),循环终止。请参阅perlop 中的 I/O 操作符。终端用户通常可以通过 来实现这一点Ctrl-d。
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