Sre*_*ova 8 php laravel laravel-5.2 laravelcollective
我有一个表单,里面我有一些选项,我使用Laravel Collective Forms来构建它,我有类似的东西:
{!! Form::select('size', $data, $selecteds, ['multiple' => true]) !!}
Run Code Online (Sandbox Code Playgroud)
一切顺利,直到这里,但现在我需要data-section为每个选项设置一个属性,我该怎么做呢?
小智 5
我最近不得不做同样的事情。在检查FormBuilder类以编写自己的marco之后,我发现select()方法实际上具有未记录的选项属性的第五个参数:
Form::select('size', $data, $selecteds, ['multiple' => true], $optionAttributes)
索引必须与选项的值匹配,例如:
$optionAttributes = [
'S' => [
'data-title' => 'Small',
'data-surcharge' => '0',
],
'M' => [
'data-title' => 'Medium',
'data-surcharge' => '5',
],
'L' => [
'data-title' => 'Large',
'data-surcharge' => '10',
],
];
Run Code Online (Sandbox Code Playgroud)
因此,我最终写了一个marco,该marco根据一个集合生成此数组,然后使用默认的select()方法。像这样:
\Form::macro('locationSelect', function ($name, $value = null, $attributes = []) {
// Get all locations from the DB
$locations = \App\Location::all();
// Make an id=>title Array for the <option>s
$list = $locations->pluck('title', 'id')->toArray();
// Generate all data-attributes per option
$optionAttributes = [];
foreach ($locations as $location) {
$optionAttributes[$location->id] = [
'data-icon' => $location->icon,
'data-something' => $location->some_attribute,
];
}
// Use default select() method of the FormBuilder
return $this->select($name, $list, $value, $attributes, $optionAttributes);
});
Run Code Online (Sandbox Code Playgroud)
很方便。
{{ Form::locationSelect('location_id') }}
将其添加到第四个参数,该参数是一个数组:
{!! Form::select('size', $data, $selecteds, ['data-attribute' => 'John Smith', 'multiple' => true]) !!}
Run Code Online (Sandbox Code Playgroud)