将列表转换为scala中的多个元组

Question

我有以下元组:(1,"3idiots",List("Action","Adventure","Horror")我需要转换为以下格式的列表:

List(
  (1,"3idiots","Action"),
  (1,"3idiots","Adventure")
)

Answer 1

要添加到以前的答案,您还可以在这种情况下使用for-understanding ; 它可能会使事情更清楚恕我直言:

for(
     (a,b,l) <- ts; 
     s <- l
) yield (a,b,s)

所以如果你有:

val ts = List(
  ("a","1", List("foo","bar","baz")),
  ("b","2", List("foo1","bar1","baz1"))
)

你会得到:

List(
      (a,1,foo), 
      (a,1,bar), 
      (a,1,baz),
      (b,2,foo1), 
      (b,2,bar1), 
      (b,2,baz1)
 )