如何从具有匹配属性的数组中删除对象？

Question

请考虑以下数据:

food = {
  id: 1,
  name: 'Pizza',
  price: 16
};

orders = [
  { food_id: 2, table_id: 5 },
  { food_id: 2, table_id: 5 },
  { food_id: 1, table_id: 5 },
  { food_id: 3, table_id: 5 },
  { food_id: 1, table_id: 5 }
];

我想从orders数组匹配中删除单个项目food_id.这是我试过的:

removeFoodOrder(food: Food): void {
  for (let order of this.orders) {
    let match = this.orders.filter((order) => order.food_id == food.id);
    match ? this.orders.splice(this.orders.indexOf(order), 1) : null;
    break;
  }
  console.log(this.orders);
}

如果我调用removeFoodOrder(food)它,它会从数组中删除第一个元素,无论我在params中传递了什么食物.

removeFoodOrder(food) 
// removes {food_id: 2, table_id: 5} (the first element)
// I want to remove {food_id: 1, table_id: 5},

我想从数组中定位匹配元素并删除它的单个实例.我哪里做错了？

Answer 1

你可以使用方法:Array#filter

food = {
  id: 1,
  name: 'Pizza',
  price: 16
};

orders = [
  { food_id: 2, table_id: 5 },
  { food_id: 2, table_id: 5 },
  { food_id: 1, table_id: 5 },
  { food_id: 3, table_id: 5 },
  { food_id: 1, table_id: 5 }
];

removeFoodOrder = (food: Food): void => {
  this.orders = this.orders.filter(order => order.food_id !== food.id);        
}

编辑:

由于您的数组允许重复元素,并且您只想删除第一个匹配项,因此您可以使用以下方法:Array#findIndex

const index = orders.findIndex(order => order.food_id === food.id);
orders.splice(index, 1);