当type.IsGenericType
= 时,我需要一些方法来获取类型的名称true
.
Type t = typeof(List<String>);
MessageBox.Show( ..?.. );
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我想要的是一个弹出消息框,List
显示......我该怎么做?
yoy*_*oyo 55
您可以实现扩展方法来获取类型的"友好名称",如下所示:
public static class TypeNameExtensions
{
public static string GetFriendlyName(this Type type)
{
string friendlyName = type.Name;
if (type.IsGenericType)
{
int iBacktick = friendlyName.IndexOf('`');
if (iBacktick > 0)
{
friendlyName = friendlyName.Remove(iBacktick);
}
friendlyName += "<";
Type[] typeParameters = type.GetGenericArguments();
for (int i = 0; i < typeParameters.Length; ++i)
{
string typeParamName = GetFriendlyName(typeParameters[i]);
friendlyName += (i == 0 ? typeParamName : "," + typeParamName);
}
friendlyName += ">";
}
return friendlyName;
}
}
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在您的项目中,您现在可以说:
MessageBox.Show(t.GetFriendlyName());
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它将显示"List <String>".
我知道OP没有要求泛型类型参数,但我更喜欢它.;-)
命名空间,内置类型的标准别名以及StringBuilder的使用留给读者练习.;-)
Luk*_*keH 36
Type t = ...;
if (t.IsGenericType)
{
Type g = t.GetGenericTypeDefinition();
MessageBox.Show(g.Name); // displays "List`1"
MessageBox.Show(g.Name.Remove(g.Name.IndexOf('`'))); // displays "List"
}
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Nic*_*ick 19
我接受了yoyo的方法.确保更原始的友好名称,处理数组,并递归处理嵌套泛型.还有单元测试.
private static readonly Dictionary<Type, string> _typeToFriendlyName = new Dictionary<Type, string>
{
{ typeof(string), "string" },
{ typeof(object), "object" },
{ typeof(bool), "bool" },
{ typeof(byte), "byte" },
{ typeof(char), "char" },
{ typeof(decimal), "decimal" },
{ typeof(double), "double" },
{ typeof(short), "short" },
{ typeof(int), "int" },
{ typeof(long), "long" },
{ typeof(sbyte), "sbyte" },
{ typeof(float), "float" },
{ typeof(ushort), "ushort" },
{ typeof(uint), "uint" },
{ typeof(ulong), "ulong" },
{ typeof(void), "void" }
};
public static string GetFriendlyName(this Type type)
{
string friendlyName;
if (_typeToFriendlyName.TryGetValue(type, out friendlyName))
{
return friendlyName;
}
friendlyName = type.Name;
if (type.IsGenericType)
{
int backtick = friendlyName.IndexOf('`');
if (backtick > 0)
{
friendlyName = friendlyName.Remove(backtick);
}
friendlyName += "<";
Type[] typeParameters = type.GetGenericArguments();
for (int i = 0; i < typeParameters.Length; i++)
{
string typeParamName = typeParameters[i].GetFriendlyName();
friendlyName += (i == 0 ? typeParamName : ", " + typeParamName);
}
friendlyName += ">";
}
if (type.IsArray)
{
return type.GetElementType().GetFriendlyName() + "[]";
}
return friendlyName;
}
[TestFixture]
public class TypeHelperTest
{
[Test]
public void TestGetFriendlyName()
{
Assert.AreEqual("string", typeof(string).FriendlyName());
Assert.AreEqual("int[]", typeof(int[]).FriendlyName());
Assert.AreEqual("int[][]", typeof(int[][]).FriendlyName());
Assert.AreEqual("KeyValuePair<int, string>", typeof(KeyValuePair<int, string>).FriendlyName());
Assert.AreEqual("Tuple<int, string>", typeof(Tuple<int, string>).FriendlyName());
Assert.AreEqual("Tuple<KeyValuePair<object, long>, string>", typeof(Tuple<KeyValuePair<object, long>, string>).FriendlyName());
Assert.AreEqual("List<Tuple<int, string>>", typeof(List<Tuple<int, string>>).FriendlyName());
Assert.AreEqual("Tuple<short[], string>", typeof(Tuple<short[], string>).FriendlyName());
}
}
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假设你只是想看到它List<T>
而不是List<string>
你需要做的:
MessageBox.Show(t.GetGenericTypeDefinition().FullName)
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请参阅http://msdn.microsoft.com/en-us/library/system.type.getgenerictypedefinition.aspx
public static class TypeNameExtensions
{
public static string GetFriendlyName(this Type type)
{
var friendlyName = type.Name;
if (!type.IsGenericType) return friendlyName;
var iBacktick = friendlyName.IndexOf('`');
if (iBacktick > 0) friendlyName = friendlyName.Remove(iBacktick);
var genericParameters = type.GetGenericArguments().Select(x => x.GetFriendlyName());
friendlyName += "<" + string.Join(", ", genericParameters) + ">";
return friendlyName;
}
}
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这是我对此的看法.我没有进行反复检查,因为我看到它总是在那里.如果你愿意,你可以添加它,但我喜欢保持简单.
public static string GetFriendlyName(this Type type)
{
if (type.IsGenericType)
{
var name = type.Name.Substring(0, type.Name.IndexOf('`'));
var types = string.Join(",", type.GetGenericArguments().Select(GetFriendlyName));
return $"{name}<{types}>";
}
else
{
return type.Name;
}
}
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我知道这是一个老问题,但我和一位同事需要为一些智能感知/roslyn 工作做这件事。最优解似乎是阿里的解,但对嵌套类型不起作用:
int i = 1; //would work
List<string> listTest = new List<string>(); //would work
Dictionary<string, int> dictTest = new Dictionary<string, int>(); //would work
Dictionary<int, List<string>> nestTest = new Dictionary<int, List<string>>(); //would fail
Dictionary<int, List<Dictionary<string, List<object>>>> superNestTest = new Dictionary<int, List<Dictionary<string, List<object>>>>(); //would fail
Dictionary<int, List<Dictionary<string, int>>> superNestTest2 = new Dictionary<int, List<Dictionary<string, int>>>(); //would fail
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为了解决这些问题,我将函数转换为递归方法:
public static class TypeExtensions
{
public static string GetFriendlyName(this Type type)
{
string friendlyName = type.FullName;
if (type.IsGenericType)
{
friendlyName = GetTypeString(type);
}
return friendlyName;
}
private static string GetTypeString(Type type)
{
var t = type.AssemblyQualifiedName;
var output = new StringBuilder();
List<string> typeStrings = new List<string>();
int iAssyBackTick = t.IndexOf('`') + 1;
output.Append(t.Substring(0, iAssyBackTick - 1).Replace("[", string.Empty));
var genericTypes = type.GetGenericArguments();
foreach (var genType in genericTypes)
{
typeStrings.Add(genType.IsGenericType ? GetTypeString(genType) : genType.ToString());
}
output.Append($"<{string.Join(",", typeStrings)}>");
return output.ToString();
}
}
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为前面的示例/测试用例运行产生以下输出:
System.Int32
System.Collections.Generic.List<System.String>
System.Collections.Generic.Dictionary<System.String,System.Int32>
System.Collections.Generic.Dictionary<System.Int32,System.Collections.Generic.List<System.String>>
System.Collections.Generic.Dictionary<System.Int32,System.Collections.Generic.List<System.Collections.Generic.Dictionary<System.String,System.Collections.Generic.List<System.Object>>>>
System.Collections.Generic.Dictionary<System.Int32,System.Collections.Generic.List<System.Collections.Generic.Dictionary<System.String,System.Int32>>>
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我花了一些时间试图解决嵌套类型问题,所以想在这里记录一下,以确保将来其他人可以节省大量时间(和头痛!)。我也检查了性能,它在微秒内完成(在最后一种情况下为 8 微秒:
性能结果
(从原始场景列表中使用的变量名称)
"i" | 43uS
"listTest" | 3uS
"dictTest" | 2uS
"nestTest" | 5uS
"superNestTest" | 9uS
"superNestTest2" | 9uS
对每个场景执行上述代码 200 次后的平均次数
Here is a complete implementation based on the previous answers supporting both Aliases (including Nullable) and Arrays:
public static class TypeNameExtensions
{
public static string GetFriendlyName(this Type type, bool aliasNullable = true, bool includeSpaceAfterComma = true)
{
TryGetInnerElementType(ref type, out string arrayBrackets);
if (!TryGetNameAliasNonArray(type, out string friendlyName))
{
if (!type.IsGenericType)
{
friendlyName = type.Name;
}
else
{
if (aliasNullable && type.GetGenericTypeDefinition() == typeof(System.Nullable<>))
{
string generics = GetFriendlyName(type.GetGenericArguments()[0]);
friendlyName = generics + "?";
}
else
{
string generics = GetFriendlyGenericArguments(type, includeSpaceAfterComma);
int iBacktick = type.Name.IndexOf('`');
friendlyName = (iBacktick > 0 ? type.Name.Remove(iBacktick) : type.Name)
+ $"<{generics}>";
}
}
}
return friendlyName + arrayBrackets;
}
public static bool TryGetNameAlias(this Type type, out string alias)
{
TryGetInnerElementType(ref type, out string arrayBrackets);
if (!TryGetNameAliasNonArray(type, out alias))
return false;
alias += arrayBrackets;
return true;
}
private static string GetFriendlyGenericArguments(Type type, bool includeSpaceAfterComma)
=> string.Join(
includeSpaceAfterComma ? ", " : ",",
type.GetGenericArguments().Select(t => t.GetFriendlyName())
);
private static bool TryGetNameAliasNonArray(Type type, out string alias)
=> (alias = TypeAliases[(int)Type.GetTypeCode(type)]) != null
&& !type.IsEnum;
private static bool TryGetInnerElementType(ref Type type, out string arrayBrackets)
{
arrayBrackets = null;
if (!type.IsArray)
return false;
do
{
arrayBrackets += "[" + new string(',', type.GetArrayRank() - 1) + "]";
type = type.GetElementType();
}
while (type.IsArray);
return true;
}
private static readonly string[] TypeAliases = {
"void", // 0
null, // 1 (any other type)
"DBNull", // 2
"bool", // 3
"char", // 4
"sbyte", // 5
"byte", // 6
"short", // 7
"ushort", // 8
"int", // 9
"uint", // 10
"long", // 11
"ulong", // 12
"float", // 13
"double", // 14
"decimal", // 15
null, // 16 (DateTime)
null, // 17 (-undefined-)
"string", // 18
};
}
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Tested with nonsense such as:
var type = typeof(Dictionary<string[,], List<int?[,][]>[,,]>[]);
var name = type.GetFriendlyName();
Console.WriteLine(name);
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And it does indeed return: "Dictionary<string[,], List<int?[,][]>[,,]>[]"
Edit: Updated to properly handle enum
types.