-5 php database mysqli database-update
请参考下面的代码.我正在使用phpMyAdmin将我的数据存储在xampp中(作为我的服务器).我找到了这段代码并添加到我的网站中.我的问题是; 如何将结果保存在数据库中.任何人??
<!DOCTYPE html>
<html>
<head>
<title>Geo City Locator by geoip-db.com</title>
</head>
<body>
<div>Country: <span id="country"></span></div>
<div>State: <span id="state"></span></div>
<div>City: <span id="city"></span></div>
<div>Postal: <span id="postal"></span></div>
<div>Latitude: <span id="latitude"></span></div>
<div>Longitude: <span id="longitude"></span></div>
<div>IP address: <span id="ipv4"></span></div>
</body>
<script>
var country = document.getElementById('country');
var state = document.getElementById('state');
var city = document.getElementById('city');
var postal = document.getElementById('postal');
var latitude = document.getElementById('latitude');
var longitude = document.getElementById('longitude');
var ip = document.getElementById('ipv4');
function callback(data)
{
country.innerHTML = data.country_name;
state.innerHTML = data.state;
city.innerHTML = data.city;
postal.innerHTML = data.postal;
latitude.innerHTML = data.latitude;
longitude.innerHTML = data.longitude;
ip.innerHTML = data.IPv4;
}
var script = document.createElement('script');
script.type = 'text/javascript';
script.src = 'https://geoip-db.com/json/geoip.php?jsonp=callback';
var h = document.getElementsByTagName('script')[0];
h.parentNode.insertBefore(script, h);
</script>
</html>Run Code Online (Sandbox Code Playgroud)
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