如何使用休眠过滤器过滤休眠中的实体

Question

我需要过滤对象列表中的实体，例如：

public class Student {

    private int id;

    private List<Course> courses;

}

public class Course {

    private int id;

    private String name;

    private float note;

    private Classroom classroom;

}

public class Classroom {

    private int id;

    private String classroom;

} 

如何获得一个包含笔记大于 70 且位于教室 23（例如）的课程列表的学生对象？

有没有办法使用实体的名称而不是数据库的列之一？

或者我如何将 hibernate 为实体生成的别名与 sql 相关联？

我附上了一个来自休眠过滤器的链接：https : //docs.jboss.org/hibernate/orm/5.0/manual/en-US/html/ch19.html

Answer 1

好的，它认为这应该可以解决问题：

实体

public class Student {

    private int id;

    @OneToMany(mappedBy = "student")
    @Filter(name = "defaultCoursesFilter")   
    private List<Course> courses;

}

@FilterDef(name = "defaultCoursesFilter"
                , defaultCondition=" notes > 70")
public class Course {

    private int id;

    private String name;

    private float note;

    @ManyToOne
    @Filter(name = "defaultClassromFilter")
    private Classroom classroom;

}


@FilterDef(name = "defaultClassromFilter"
                , defaultCondition=" id  = 23")
public class Classroom {

    private int id;

    private String classroom;

} 

查询前

Session session = sessionFactory.getCurrentSession();
session.enableFilter("defaultCoursesFilter");
session.enableFilter("defaultClassromFilter");

// query