在C++中使用运算符重载

Question

class A
{
public:
    ostream& operator<<(int  string)
    {
        cout << "In Overloaded function1\n";
        cout << string << endl;
    }
};

main()
{
    int temp1 = 5;
    char str = 'c';
    float p= 2.22;
    A a;
    (a<<temp1);
    (a<<str);
    (a<<p);
    (a<<"value of p=" << 5);
}

我希望输出为:p = 5的值

应该做什么改变...并且函数应该接受传递的所有数据类型

Answer 1

有两种解决方案.

第一种解决方案是使其成为模板.

            template <typename T>
            ostream& operator<<(const T& input) const
            {
                    cout << "In Overloaded function1\n";
                    return (cout << input << endl);
             }

然而,这将使a << str与a << p打印c和2.22,这是从原始的代码不同.输出99和2.

第二个解决方案是简单地添加一个重载函数const char*:

            ostream& operator<<(int  string)
            {
                    cout << "In Overloaded function1\n";
                    return (cout << string << endl);
             }

            ostream& operator<<(const char*  string)
            {
                    cout << "In Overloaded function1\n";
                    return (cout << string << endl);
             }

这使得C字符串,一切都转换为int要A <<"版,但仅此而已-它不会'接受所传递的所有数据类型’.

顺便说一句,你已经忘记return了ostream.