我正忙着在Swiftty操场上用SwiftyJSON解析JSON.我的代码如下:
import UIKit
import SwiftyJSON
var partyList: [String] = []
var firstPresidentList: [String] = []
if let url = URL(string:"http://mysafeinfo.com/api/data?list=presidents&format=json") {
if let data = try? Data(contentsOf: url) {
let json = JSON(data: data)
for i in 1...43 {
let party = json[i]["pp"].stringValue
let president = json[i]["nm"].stringValue
if partyList.contains(party) {
print("\n")
} else {
partyList.append(party)
firstPresidentList.append(president)
}
}
print("All the different parties of U.S. presidents included "+partyList.joined(separator: ", ")+", in that order. The first presidents of those parties were (repectively) "+firstPresidentList.joined(separator: ", ")+".")
}
}
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在print行,我不知道我怎么会是最后一个前用逗号和空格加入阵列像我有,但增加"和".
谢谢!
fre*_*tag 14
由于 iOS 13.0+ / macOS 10.15+ Apple 提供了ListFormatter。另请参阅此处了解详细信息。
数组可以简单地格式化为:
let elements = ["a", "b", "c"]
result = ListFormatter.localizedString(byJoining: elements)
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顾名思义,您还可以免费获得本地化。
Leo*_*bus 13
添加一个条件来检查你的String集合是否小于或等于2个元素,如果为true则只返回连接的两个元素," and "否则删除集合的最后一个元素,用分隔符连接元素", "然后重新添加最后一个元素最终分隔符", and ".
您可以将BidirectionalCollection协议约束的协议扩展到StringProtocol:
双向集合提供从任何有效索引向后遍历,不包括集合的startIndex.因此,双向集合可以提供额外的操作,例如提供对最后一个元素的有效访问的最后一个属性,以及以相反顺序呈现元素的reverse()方法.
Swift 4.2或更高版本
extension BidirectionalCollection where Element: StringProtocol {
var sentence: String {
guard let last = last else { return "" }
return count <= 2 ? joined(separator: " and ") :
dropLast().joined(separator: ", ") + ", and " + last
}
}
let elements = ["a", "b", "c"]
let sentenceFromElements = elements.sentence // "a, b, and c"
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斯威夫特4
extension BidirectionalCollection where Iterator.Element == String, SubSequence.Iterator.Element == String {
var sentence: String {
guard let last = last else { return "" }
return count <= 2 ? joined(separator: " and ") :
dropLast().joined(separator: ", ") + ", and " + last
}
}
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Swift 3.1或更高版本
extension Array where Element == String {
var sentence: String {
guard let last = last else { return "" }
return count <= 2 ? joined(separator: " and ") :
dropLast().joined(separator: ", ") + ", and " + last
}
}
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