使用 NamedParameterJdbcTemplate 将数据发送到数据库

Question

package com.techm.template;
import java.sql.Types;
import java.util.Date;
import java.util.HashMap;
import java.util.Map;

import javax.sql.DataSource;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate;
import org.springframework.jdbc.core.namedparam.SqlParameterSource;
import org.springframework.jdbc.datasource.DriverManagerDataSource;

public class InsertRecordInDatabaseWithJdbcTemplate {

    private static final String driverClassName = "oracle.jdbc.driver.OracleDriver";

    private static final String url = "jdbc:oracle:thin:@localhost:1521:xe";

    private static final String dbUsername = "SYSTEM";

    private static final String dbPassword = "9848451415";

    private static final String sql = "INSERT INTO employee(firstname,lastname,username,password) VALUES(?,?,?,?)";


    private static DataSource dataSource;



    public static void main(String[] args) throws Exception {

        dataSource = getDataSource();

        Employee e = new Employee();
        e.setFirstname("Surya Teja");
        e.setLastname("Tammana");
        e.setUsername("surya_kvm");
        e.setPassword("9848451415");

        int result = saveRecord(e);
        if(result != 0){
            System.out.println("Success");
        }
        else{
            System.out.println("Failure");
        }

    }



   public static int saveRecord(Employee e) {

       NamedParameterJdbcTemplate template = new NamedParameterJdbcTemplate(dataSource);

       SqlParameterSource params = new MapSqlParameterSource();

       Map<String, Object> parameters = new HashMap<String, Object>();
        parameters.put("firstnames", e.getFirstname());
        parameters.put("lastname", e.getLastname());
        parameters.put("username", e.getUsername());
        parameters.put("password", e.getPassword());

        int result = template.update(sql, parameters);
        return result;
   }



 public static DriverManagerDataSource getDataSource() {

 DriverManagerDataSource dataSource = new DriverManagerDataSource();
 dataSource.setDriverClassName(driverClassName);
 dataSource.setUrl(url);
 dataSource.setUsername(dbUsername);
 dataSource.setPassword(dbPassword);
 return dataSource;

    }
}   

雇员.java

package com.techm.template;

public class Employee {

private String firstname;
private String lastname;
private String username;
private String password;
public String getFirstname() {
    return firstname;
}
public void setFirstname(String firstname) {
    this.firstname = firstname;
}
public String getLastname() {
    return lastname;
}
public void setLastname(String lastname) {
    this.lastname = lastname;
}
public String getUsername() {
    return username;
}
public void setUsername(String username) {
    this.username = username;
}
public String getPassword() {
    return password;
}
public void setPassword(String password) {
    this.password = password;
}




}

安慰

2017 年 1 月 22 日上午 12:25:24 org.springframework.jdbc.datasource.DriverManagerDataSource setDriverClassName 信息：加载的 JDBC 驱动程序：oracle.jdbc.driver.OracleDriver 线程“main”org.springframework.dao.InvalidDataAccessApiUserTException 中的异常：SQL [INSER] INTO员工（名字，姓氏，用户名，密码）VALUES（？，？，？，？）]：在org.springframework.jdbc.core.PreparedStatementCreatorFactory$PreparedStatementCreatorImpl.(PreparedStatementCreatorFactory.java:221)处给出4个参数但预期为0 org.springframework.jdbc.core.PreparedStatementCreatorFactory$PreparedStatementCreatorImpl.(PreparedStatementCreatorFactory.java:199) at org.springframework.jdbc.core.PreparedStatementCreatorFactory.newPreparedStatementCreator(PreparedStatementCreator3corework.java:org.springframework.jdbc.core.PreparedStatementCreatorFactory.newPreparedStatementCreator(PreparedStatementCreator3core.java:NamedParameterJdbcTemplate.getPreparedStatementCreator(NamedParameterJdbcTemplate.java:351) 在 org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.update(NamedParameterJdbcTemplate.java:287) 在 org.springframework.jdbc.core.namedTemplateNamedParameter. 292) 在 com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64) 在 com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.main(InsertRecordInDatabaseWithJdbcTemplate.java:update(NamedParameterJdbcTemplate.java:292) at com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64) at com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.main(InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64)update(NamedParameterJdbcTemplate.java:292) at com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64) at com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.main(InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64)

Answer 1

您在 SQL 查询中使用位置参数。这不起作用，因为您正在使用NamedParameterJdbcTemplate需要命名参数的 。只需修改您的查询以使用这样的命名参数：

"INSERT INTO employee(firstname, lastname, username, password) VALUES(:firstname, :lastname, :username, :password)"

您也可以使用 Employee 对象作为参数源：

public static int saveRecord(Employee e) {
        NamedParameterJdbcTemplate template = new NamedParameterJdbcTemplate(dataSource);

        SqlParameterSource params = new BeanPropertySqlParameterSource(e);

        int result = template.update(sql, params);
        return result;
   }

在BeanPropertySqlParameterSource将员工使用属性来设置参数。