Django版本:1.10.4异常类型:ValueError
Exception Value:
"<SchoolBook: 0 test1 Test2 Test3 2011 122>" needs to have a value for field "schoolbook" before this many-to-many relationship can be used.
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请帮助避免此错误:
class Subject(models.Model):
name = models.CharField(max_length=256)
slug = models.SlugField(max_length=256, blank=True)
def __str__(self):
return self.name
def save(self, *args, **kwargs):
if not self.id:
self.slug = slugify(self.name, separator='_')
return super(Subject, self).save(*args, **kwargs)
class SchoolBook(models.Model):
parent_subject = models.ManyToManyField(Subject)
year = models.SmallIntegerField()
name = models.CharField(max_length=256,blank=True)
autors = models.CharField(max_length=256)
slug = models.SlugField(max_length=256, blank=True, unique=True)
f_file = models.FileField(upload_to=directory_path)
def __str__(self):
return '{0} {1} {2}'.format(
self.name, self.autors, self.year)
def save(self, *args, **kwargs):
if not self.id:
subject_name = [self.parent_subject.values()[i]['name'] for i in range(len(self.parent_subject.values()))]
self.name = ' '.join(subject_name)
self.slug = slugify("{} {} {} {} {}".format(self.name, self.autors,self.year, self.pages, self.c_class))
return super(SchoolBook, self).save(*args, **kwargs)
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问题是当我尝试保存对象时。
保存实例之前,您无法访问多对多关系的相关对象!该实例必须具有一个id中间m2n表的,以将其外键(名称为schoolbook,因此显示错误消息)指向:
def save(self, *args, **kwargs):
if not self.id:
super(SchoolBook, self).save(*args, **kwargs)
# process self.parent_subject (should be called ...subjects, semantically)
super(SchoolBook, self).save(*args, **kwargs)
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