liw*_*ire 1 hibernate spring-mvc one-to-many circular-reference jackson
我在这个Web服务项目中使用Spring(xml + annotations),Hibernate(注释).数据库关系图,模型,预期和实际输出如下,
Customer.java
@Entity
@Table(name="customer")
public class Customer implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="customer_id", unique=true, nullable =false)
long customerId;
@Column(name="name")
String name;
@Column(name="secondary_name")
String secondaryName;
@Column(name="date")
Date date;
@Column(name="address")
String address;
@Column(name="post")
String post;
@Column(name="pin")
String pin;
@Column(name="phone")
String phone;
@OneToMany(fetch=FetchType.LAZY, mappedBy="customer", cascade=CascadeType.ALL)
@JsonManagedReference
Set<Loan> loans = new HashSet<Loan>();
//constructors, getters and setters
}
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Loan.java
public class Loan implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="loan_id", nullable=false, unique=true)
long loanId;
@ManyToOne(fetch = FetchType.EAGER, cascade=CascadeType.ALL)
@JoinColumn(name="customer_id", nullable = false)
@JsonBackReference
Customer customer;
@Column(name="date", nullable=false)
Date date;
@Column(name="amount", nullable=false)
double amount;
@OneToMany(fetch=FetchType.LAZY, mappedBy="loan", cascade=CascadeType.ALL)
@JsonManagedReference
List<Item> items = new ArrayList<Item>();
//constructors, getters, setters
}
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Item.java
public class Item implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="item_id", nullable=false, unique=true)
long itemId;
@ManyToOne(fetch=FetchType.LAZY, cascade=CascadeType.ALL)
@JoinColumn(name="loan_id", nullable = false)
@JsonBackReference
Loan loan;
@Column(name="name", nullable=false)
String name;
@Column(name="weight", nullable=false)
double weight;
//constructors, setters, getters
}
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实际输出:此处未显示客户详细信息
{
"loanId":4,
"date":1484937000000,
"amount":10000.0,
"items":[
{
"itemId":3,
"name":"Item1",
"weight":10.0
},
{
"itemId":4,
"name":"Item2",
"weight":20.0
}
]
}
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预期产出:在寻找贷款时也需要显示客户详细信息
{
"loanId":4,
"customer":{
"customerId":2,
"name":"Prem",
"address":"Street,State"
},
"date":1484937000000,
"amount":10000.0,
"items":[
{
"itemId":3,
"name":"Item1",
"weight":10.0
},
{
"itemId":4,
"name":"Item2",
"weight":20.0
}
]
}
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我可以从数据库中获取客户详细信息,但无法使用Jackson Json加载它.如果我删除@JsonManagedReference,我最终会得到循环循环.如果我删除@JsonBackReference,则输出中没有效果.完整代码:https://github.com/liwevire/TM_Service 提前致谢.
因为您在实体中使用@JsonBackReferenceon Customer属性,所以Loan该Customer对象不会包含在序列化中.在对象中使用@JsonManagedReferencefor,并在实体中的属性上使用.CustomerLoan@JsonBackReferenceLoanCustomer
这将序列化Customer您的Loan实体的属性.但是Customer对象序列化将不包含该Loan属性.您需要选择关系的一侧进行序列化.
要允许双方,请@JsonIdentityInfo在实体中使用注释并删除@JsonBackReference和@JsonManagedReference.你的实体将是这样的:
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "customerId")
public class Customer implements Serializable {
...
}
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的property的@JsonIdentityInfo参考您的实体ID属性,Customer这将是customerId.这样做对Loan和Item也.
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