C#三角学(帮助!)

Question

好的,这就是情况......

我目前正在为我的数学和物理学课程做一个项目.

我完成了解决方案的编码,并运行了我老师为我们制作的xUnit测试.

其中90%的人失败了.

我有一个Calculator.cs文件,其中包含我编码的所有方法.每个三角函数方法都返回一个元组,然后在一个xUnit.Assert.Equal中使用Tuple的项目(expectedResult,Math.Round(calculatorTuple.Item1,4)) ...

例如......我有一个名为Trig_Calculate_Adjacent_Hypotenuse的方法,它接受两个双精度作为它的参数(角度,度数和相反)

计算器发现Adjacent等于15.4235 ...但我的实际计算显示它是56.7128.因此,当测试运行时,它会执行Assert.Equal(56.7128,15.4235)并发现这两个答案不相等.(明显)

我多次查看了我的Calculator.cs文件中的代码......并且在我的生活中找不到问题.

这是我的方法,所以你可以看看它:

public static Tuple<double,double> Trig_Calculate_Adjacent_Hypotenuse(double Angle, double Opposite)
    {
        double Hypotenuse;
        double Adjacent;
        // SOH CAH TOA

        // Using TOA to find Adjacent
        // so Adjacent = Opposite / Tan(Angle)
        // so Adjacent = 10 / Tan(10)
        // which means Adjacent = 56.7128
        // However my calculator finds 15.4235 instead...
        Adjacent = Opposite / Math.Tan(Calculator.DegreesToRadians(Angle));

        // Using SOH to find Hypotenuse
        // so Hypotenuse = Opposite / Sin(Angle)
        // so Hypotenuse = 10 / Sin(10)
        // which means Hypotenuse = 57.5877
        // However my calculator finds something different... (unknown due to Adjacent's failure)
        Hypotenuse = Opposite / Math.Sin(Calculator.DegreesToRadians(Angle));

        return new Tuple<double, double>(Adjacent, Hypotenuse);
    }

这是测试方法:

        [Theory]
    // Student Data
    [InlineData(10, 10, 56.7128, 57.5877)]
    public void TestCalculateAdjacentHypotenuse(double Angle, double Opposite, double Adjacent, double Hypotenuse)
    {
        // Act - performing the action
        Tuple<double, double> results = Calculator.Trig_Calculate_Adjacent_Hypotenuse(Angle, Opposite);

        // Assert - did we get back the correct answer
        Assert.Equal(Adjacent, Math.Round(results.Item1, 4));
        Assert.Equal(Hypotenuse, Math.Round(results.Item2, 4));
    }

我希望你们能帮助我找出问题所在!:)

谢谢!

Answer 1

Math.Tan(Angle)有弧度的作品,不与学位(同样Sin(),Cos()有弧度的工作).

尝试 Math.Tan(Angle * Math.PI / 180);