自修改代码始终是Linux上的分段错误

Question

我发现了一篇关于自修改代码的文章,并试图做一些例子,但我总是得到分段错误.就像我能理解的那样,内存权限存在违规行为.代码段是(r)ead/e(x)ecute,因此写入的尝试导致此错误.有没有办法通过在运行时或之前更改内存权限来测试程序？我正在使用linux,这个例子是用GAS汇编编写的.

.extern memcpy
.section .data
string:
        .asciz  "whatever"
string_end:
.section .bss
        .lcomm buf, string_end-string
.section .text
.globl main
main:
        call changer
        mov $string, %edx
label:
        push string_end-string
        push $buf
        push $string
        call memcpy
changer:
        mov $offset_to_write, %esi
        mov $label, %edi
        mov $0xb, %ecx
loop1:
        lodsb
        stosb
        loop loop1
        ret
offset_to_write:
        push 0
        call exit
end:

所以在osgx建议的修改后,这是一个工作代码.(实际上,如果你组装并链接并运行它崩溃,但如果你看着使用gdb,它确实修改了它的代码!)

.extern memcpy
.section .data
string:
        .asciz  "Giorgos"
string_end:
.section .bss
        .lcomm buf, string_end-string
.section .text
.globl main
main:
        lea (main), %esi                # get the start of memory region to
                                        # change its permissions (smc-enabled)
        andl $0xFFFFF000, %esi          # align to start of a pagesize
        pushl   $7                      # permissions==r|w|x
        pushl   $4096                   # page size
        pushl   %esi                    # computed start address
        call    mprotect

        call    changer                 # function that does smc
        mov     $string, %edx
label:
        push    string_end-string       # this code will be overridden
        push    $buf                    # and never be executed!
        push    $string
        call    memcpy
changer:
        mov     $offset_to_write, %esi  # simple copy bytes algorithm
        mov     $label, %edi
        mov     $0xb, %ecx
loop1:
        lodsb
        stosb
        loop    loop1
        ret
offset_to_write:                        # these instructions will be
        push    $0                      # executed eventually
        call    exit
end:

Answer 1

您应该在运行时更改内存访问权限.

#include <sys/mman.h>

void *addr  = get_address_of_instruction_pointer();
int  length = 4096;   /* size of a page */

if (mprotect(addr, length, PROT_READ | PROT_WRITE | PROT_EXEC) == 0) {
    /* current code page is now writable and code from it is allowed for execution */
}

Answer 2

现代CPU具有一个名为DEP的功能,可防止在堆栈上执行代码.以前,这是可能的; 现在,事实并非如此.默认情况下,二进制文件被加载到只读内存中.

除此之外,您可以使用mprotect系统调用将内存中的二进制文件位置标记为可执行文件 - 因为您的代码不受保护.所以不要试图把代码和堆栈然后跳进去.