为什么我会收到错误"检测到无法访问的代码"？

Question

using System;

namespace G09 {
    class Reverse {
        static void Main() 
        {
            Console.WriteLine(ReverseText(24));

            Console.ReadKey();
        }

        static string ReverseText(int n) {
            if (n < 1) 
            {
                return "";
            }

            string index = "1";
            string revIndex = "";
            int count = 1;
            string[] arr = new string[n];

            for (int i = 0; i < n; i++) 
            {
                arr[i] = index + revIndex;
                for (int j = 0; j <= i; j++) 
                {
                    if (count > 8) 
                    {
                        index = index + 0;
                        count = 0;
                        break;
                    }
                    index = index + (count++ + 1).ToString();
                    break;
                }
                revIndex = "";
                for (int k = index.Length - 1; k >= 0; k--) 
                {
                    if (k == index.Length - 1) 
                    {
                        continue;
                    }
                    revIndex += index[k];
                }
            }    
            return string.Join("\n", arr);
        }
    }
}

/tmp/csharp117013-18-5s54om.vh6mt2o6r/code.cs(10,41):警告CS0162:检测到无法访问的代码

谁能告诉我为什么这行代码在第23行无法访问？我无法理解...在视觉工作室它工作正常,但在其他节目错误.

Answer 1

这j++是毫无意义的,因为break在最后,删除其中之一

for (int j = 0; j <= i; j++) {
   ...
   break;
}

Answer 2

你永远不会增加j因为你break在第一个循环之后的迭代

for (int j = 0; j <= i; j++) //<- Error here, j++ will never be reached
{
    if (count > 8)
    {
        index = index + 0;
        count = 0;
        break;
    }
    index = index + (count++ + 1).ToString();
    break; //you leave the for loop here
}