在_Layout视图中显示当前用户名

Question

我想在我的_Layout视图的导航栏上显示当前的ApplicationUsers Firstname + Lastname.我发现你可以从当前的RenderedBody控制器传递你的viewbag,如下所示:

  private readonly IHttpContextAccessor _httpContext;
    private readonly UserManager<ApplicationUser> _userManager;
    private readonly ApplicationUser _user;

    public HomeController(IHttpContextAccessor httpContextAccessor, UserManager<ApplicationUser> userManager) {
       _httpContext = httpContextAccessor;
       _userManager = userManager;
        _user = _userManager.Users.Single(u => u.Id == _httpContext.HttpContext.User.FindFirst(ClaimTypes.NameIdentifier).Value);
    }

在控制器中:

public IActionResult Index()
    {

        ViewBag.Username = $"{_user.FirstName} {_user.Surname}";
        return View();
    }

最后在我的_Layout视图中:

<strong class="font-bold">@ViewBag.Username</strong>

这种方法似乎与谷物相悖,对每一种观点来说都是一种巨大的痛苦.实现这一目标的标准是什么？

Answer 1

您可以将UserManager和插入SignInManager视图中。

@inject SignInManager<ApplicationUser> SignInManager
@inject UserManager<ApplicationUser> UserManager

然后，您可以测试用户是否使用登录SignInManager.IsSignedIn(User)并使用显示用户名UserManager.GetUserName(User)

@if (SignInManager.IsSignedIn(User))
{
  <form asp-area="" asp-controller="Account" asp-action="LogOff" method="post" id="logoutForm" class="navbar-right">
   <ul class="nav navbar-nav navbar-right">
    <li>
     <a asp-area="" asp-controller="Manage" asp-action="Index" title="Manage">Hello @UserManager.GetUserName(User)!</a>
    </li>
    <li>
      <button type="submit" class="btn btn-link navbar-btn navbar-link">Log off</button>
    </li>
   </ul>
 </form>
}

PS。还需要添加这两种using以及

@using Microsoft.AspNetCore.Identity
@using MyWebApp.Models