jQuery.ajax返回400 Bad Request

Sco*_*t B 17 ajax jquery

这很好用:

jQuery('#my_get_related_keywords').click(function() {
    if (jQuery('#my_keyword').val() == '') return false;
        jQuery.getJSON("http://boss.yahooapis.com/ysearch/web/v1/"
        +jQuery('#my_keyword').val()+"?"
        +"appid=myAppID"
        +"&lang=en"
        +"&format=json"
        +"&count=50"
        +"&view=keyterms"
        +"&callback=?",
        function (data) {//do something}
Run Code Online (Sandbox Code Playgroud)

这将返回400 Bad Request(仅使用.ajax重构上述jQuery以支持错误处理).

jQuery('#my_get_related_keywords').click(function()
    {
    if (jQuery('#my_keyword').val() == '') return false; 
    jQuery('#my_loader').show();
    jQuery.ajax(
        {
        url: "http://boss.yahooapis.com/ysearch/web/v1/"
        +jQuery('#my_keyword').val()+"?"
        +"appid=myAppID"
        +"&lang=en"
        +"&format=json"
        +"&count=50"
        +"&view=keyterms"
        +"&callback=?", 
        success: function(data)
            {//do something}
Run Code Online (Sandbox Code Playgroud)

And*_*rri 19

我想你只需要添加2个选项(contentTypedataType):

$('#my_get_related_keywords').click(function() {

    $.ajax({
            type: "POST",
            url: "HERE PUT THE PATH OF YOUR SERVICE OR PAGE",
            data: '{"HERE YOU CAN PUT DATA TO PASS AT THE SERVICE"}',
            contentType: "application/json; charset=utf-8", // this
            dataType: "json", // and this
            success: function (msg) {
               //do something
            },
            error: function (errormessage) {
                //do something else
            }
        });
}
Run Code Online (Sandbox Code Playgroud)


lig*_*ght 11

将此添加到您的ajax调用:

contentType: "application/json; charset=utf-8",
dataType: "json"
Run Code Online (Sandbox Code Playgroud)


bhi*_*pas 7

迟到的答案,但我认为值得保持更新.扩展Andrea Turri的答案以反映更新的jQuery API和.success/.error已弃用的方法.

从jQuery 1.8.*开始,首选的方法是使用.done()和.fail().Jquery文档

例如

$('#my_get_related_keywords').click(function() {

    var ajaxRequest = $.ajax({
        type: "POST",
        url: "HERE PUT THE PATH OF YOUR SERVICE OR PAGE",
        data: '{"HERE YOU CAN PUT DATA TO PASS AT THE SERVICE"}',
        contentType: "application/json; charset=utf-8",
        dataType: "json"});

    //When the request successfully finished, execute passed in function
    ajaxRequest.done(function(msg){
           //do something
    });

    //When the request failed, execute the passed in function
    ajaxRequest.fail(function(jqXHR, status){
        //do something else
    });
});
Run Code Online (Sandbox Code Playgroud)