如何将变量传递给Laravel 5.3中的内部函数?

zka*_*oca 1 php function laravel eloquent

我试图将语言环境数据传递给雄辩的查询,但它无法得到它.$locale值来自URI.

class MyController extends Controller
{

    public function index($locale = 'en')
    {
        $news = News::join('categories', 'categories.id', '=', 'news.catid')
            ->select('news.*', 'categories.category')
            ->where([['news.published', '1'], ['news.deleted', '0']])
            ->where(function ($query) {
                $query->where('news.language', $locale) //$locale is not recognized naturally
                      ->orWhere('news.language', 'all');
            })
            ->orderBy('news.published_at', 'desc')
            ->take(4)
            ->get();

             .
             .
             .
    }
}
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如何将$locale值传递给子查询?

Jef*_*ert 7

还有就是use,你可以用它来创建一个结构封闭周围的变量:

->where(function ($query) use($locale) {
    $query->where('news.language', $locale) 
          ->orWhere('news.language', 'all');
})
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请参见手册 "从父作用域继承变量" 中的示例#3 .