考虑以下代码:
public void convertTime()
{
DateFormat df = new SimpleDateFormat(dateFormat);
Date date;
Date date2;
date = df.parse("15/01/2010 21:58:54");
date.getTime(); //produces 1263585534000
date2 = new Date(date.getTime()); //this is ok, compiles
date2 = new Date(1263585534000); //gives an error: The literal 1263585534000 of type int is out of range
}
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我想知道如何将这个长数字转换为日期格式,为什么我会收到此错误?
谢谢
1263585534000大于2 ^ 31-1.使用L指示长.
date2 = new Date(1263585534000L);
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