Chr*_*ian 6 android android-layout android-drawable android-graphics android-vectordrawable
在我的Android应用程序中,我想知道用户点击的点与特定的VectorDrawable组之间的距离.
我希望距离像blue
VectorDrawable中的组一样:
<vector android:height="24dp" android:viewportHeight="1052.3622"
android:viewportWidth="744.0945" android:width="24dp" xmlns:android="http://schemas.android.com/apk/res/android">
<path android:fillColor="#ff0000"
android:name="blue"
android:pathData="M182.9,349.5m-74.7,0a74.7,74.7 0,1 1,149.3 0a74.7,74.7 0,1 1,-149.3 0"
android:strokeAlpha="1" android:strokeColor="#000000" android:strokeWidth="4.23501825"/>
<path android:fillColor="#00ff00"
android:name="red"
android:pathData="M474.3,392.4a84.3,102.9 0,1 0,168.6 0a84.3,102.9 0,1 0,-168.6 0z"
android:strokeAlpha="1" android:strokeColor="#000000" android:strokeWidth="5"/>>
</vector>
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在Android中有一种直接的方法来计算这个距离吗?
我不确定是否存在解决该问题的简单方法,但可以这样做:
解析向量 XML,以便您在运行时拥有所有这些变量。这里不讨论解析,假设您有以下数据结构,我们稍后将使用它:
private static class VectorData {
private int width = 24;
private int height = 24;
private double viewportHeight = 1052.3622;
private double viewportWidth = 744.0945;
private String path = "M182.9,349.5m-74.7,0a74.7,74.7 0,1 1,149.3 0a74.7,74.7 0,1 1,-149.3 0";
private double scaleVectorX(Context context) {
return dpToPx(context, width) / viewportWidth;
}
private double scaleVectorY(Context context) {
return dpToPx(context, height) / viewportHeight;
}
private static float dpToPx(Context context, float dp) {
return dp * context.getResources().getDisplayMetrics().density;
}
}
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如您所见,为了简单起见,所有字段都进行了硬编码。
下一步是解析矢量路径数据,将其转换为 android.graphics.Path:
android.graphics.Path path = android.util.PathParser.createPathFromPathData(vectorData.path);
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android.util.PathParser 不包括在内,但您可以在这里找到源代码: https: //android.googlesource.com/platform/frameworks/base/+/17e64ffd852f8fe23b8e2e2ff1b62ee742af17a6/core/java/android/util/PathParser.java。但不确定复制和使用它是否合法。
有了路径,我们需要找到它的 N 个点(坐标)。更多的点 - 更精确的结果将是和更慢的处理:
final Collection<Point> points = getPoints(path, iv.getX(), iv.getY(), vectorData);
private static class Point {
private float x;
private float y;
Point(float x, float y) {
this.x = x;
this.y = y;
}
@Override
public String toString() {
return "Point{" +
"x=" + x +
", y=" + y +
'}';
}
}
private Collection<Point> getPoints(Path path, float viewX, float viewY, VectorData vectorData) {
Collection<Point> points = new ArrayList<>();
PathMeasure pm = new PathMeasure(path, false);
float length = pm.getLength();
float distance = 0f;
int size = N;
float speed = length / size;
int counter = 0;
float[] aCoordinates = new float[2];
while ((distance < length) && (counter < size)) {
// get point from the path
pm.getPosTan(distance, aCoordinates, null);
float pathX = aCoordinates[0];
float pathY = aCoordinates[1];
float x = (float) (vectorData.scaleVectorX(this) * pathX) + viewX;
float y = (float) (vectorData.scaleVectorY(this) * pathY) + viewY;
points.add(new Point(x, y));
counter++;
distance = distance + speed;
}
return points;
}
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path - 是我们之前得到的路径,iv - 是矢量容器(例如ImageView),我们需要它来调整点坐标。vectorData - 是我们在解析向量之前获得的结构。
现在我们需要定义区域来处理路径闭合的情况,并且我们希望将路径内的单击视为 0 距离:
final Region region = new Region();
RectF rectF = new RectF();
path.computeBounds(rectF, true);
region.setPath(path, new Region((int) rectF.left, (int) rectF.top, (int) rectF.right, (int) rectF.bottom));
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为了计算最小距离,应使用以下方法:
private int getMinDistance(float eventX, float eventY, Collection<Point> pathPoints, Region pathRegion, VectorData vectorData) {
int minDistance = Integer.MAX_VALUE;
boolean contains = pathRegion.contains((int) (eventX / vectorData.scaleVectorX(this)), (int) (eventY / vectorData.scaleVectorY(this)));
if (contains) {
minDistance = 0;
} else {
for (Point point : pathPoints) {
int distance = getDistanceBetweenPoints((int) eventX, (int) eventY, (int) point.x, (int) point.y);
if (distance < minDistance) {
minDistance = distance;
}
}
}
return minDistance;
}
private int getDistanceBetweenPoints(int x, int y, int x1, int y1) {
return (int) Math.sqrt((x1 - x) * (x1 - x) + (y1 - y) * (y1 - y));
}
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