Java - 方法参数,String后跟List

Question

我有一个接受a String和String<List>as方法参数的Java方法.如何区分String和不属于List？

方法:

void returnValues(String sensor, List<String> attributes)

呼叫:

nexaConnect.returnValues(Arrays.asList("19455746", "blobJson", "deviceMfg", "eventCode", "sensorClass", "sensorUUID", "timeStamp", "uID"));

我能看到的唯一可能的工作是删除第一个String并在List中包含值,然后获取列表的第一个值并以这种方式使用它.有没有办法将它们分开,以便它不是列表的一部分？

Answer 1

调用尝试returnValues与形式参数不匹配.假设这就是你要问的,那就像这样.

nexaConnect.returnValues("TheFirst", Arrays.asList("19455746", "blobJson", 
    "deviceMfg", "eventCode", "sensorClass", 
    "sensorUUID", "timeStamp", "uID"));

或保存对局部变量的引用,看起来像,

String sensor = "TheFirst";
List<String> attributes = Arrays.asList("19455746", "blobJson", 
    "deviceMfg", "eventCode", "sensorClass", 
    "sensorUUID", "timeStamp", "uID");
nexaConnect.returnValues(sensor, attributes);