Ste*_*ios 0 python audio mp4 wav
我想将Facebook Messenger的录音转换为文本.以下是使用Facebook的API发送.mp4文件的示例:https://cdn.fbsbx.com/v/t59.3654-21/15720510_10211855778255994_5430581267814940672_n.mp4/audioclip-1484407992000-3392.mp4?oh=a78286aa96c9dea29e5d07854194801c&oe =587C3833
所以这个文件只包含音频(不是视频),我想将其转换为文本.
此外,我想尽快做到这一点,因为我将在几乎实时的应用程序中使用生成的文本(即用户发送.mp4文件,脚本将其转换为文本并显示回来).
我找到了这个例子https://github.com/Uberi/speech_recognition/blob/master/examples/audio_transcribe.py ,这里是我使用的代码:
import requests
import speech_recognition as sr
url = 'https://cdn.fbsbx.com/v/t59.3654-21/15720510_10211855778255994_5430581267814940672_n.mp4/audioclip-1484407992000-3392.mp4?oh=a78286aa96c9dea29e5d07854194801c&oe=587C3833'
r = requests.get(url)
with open("test.mp4", "wb") as handle:
for data in r.iter_content():
handle.write(data)
r = sr.Recognizer()
with sr.AudioFile('test.mp4') as source:
audio = r.record(source)
command = r.recognize_google(audio)
print command
Run Code Online (Sandbox Code Playgroud)
但是我收到了这个错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Users\Asterios\Anaconda2\lib\site-packages\speech_recognition\__init__.py", line 200, in __enter__
self.audio_reader = aifc.open(aiff_file, "rb")
File "C:\Users\Asterios\Anaconda2\lib\aifc.py", line 952, in open
return Aifc_read(f)
File "C:\Users\Asterios\Anaconda2\lib\aifc.py", line 347, in __init__
self.initfp(f)
File "C:\Users\Asterios\Anaconda2\lib\aifc.py", line 298, in initfp
chunk = Chunk(file)
File "C:\Users\Asterios\Anaconda2\lib\chunk.py", line 63, in __init__
raise EOFError
EOFError
Run Code Online (Sandbox Code Playgroud)
有任何想法吗?
编辑:我想在pythonanywhere.com的免费计划上运行脚本,所以我不知道如何在那里安装像ffmpeg这样的工具.
编辑2:如果你运行上面的脚本用这个url代替url" http://www.wavsource.com/snds_2017-01-08_2348563217987237/people/men/about_time.wav "并将'mp4'改为'wav',它工作正常.所以它肯定是文件格式的东西.
Ste*_*ios 10
最后我找到了解决方案.我在这里发布它,以防它将来帮助某人.
幸运的是,pythonanywhere.com预装了avconv(avconv类似于ffmpeg).
所以这里有一些有用的代码:
import urllib2
import speech_recognition as sr
import subprocess
import os
url = 'https://cdn.fbsbx.com/v/t59.3654-21/15720510_10211855778255994_5430581267814940672_n.mp4/audioclip-1484407992000-3392.mp4?oh=a78286aa96c9dea29e5d07854194801c&oe=587C3833'
mp4file = urllib2.urlopen(url)
with open("test.mp4", "wb") as handle:
handle.write(mp4file.read())
cmdline = ['avconv',
'-i',
'test.mp4',
'-vn',
'-f',
'wav',
'test.wav']
subprocess.call(cmdline)
r = sr.Recognizer()
with sr.AudioFile('test.wav') as source:
audio = r.record(source)
command = r.recognize_google(audio)
print command
os.remove("test.mp4")
os.remove("test.wav")
Run Code Online (Sandbox Code Playgroud)
在免费计划中,cdn.fbsbx.com
不在pythonanywhere上的白名单上,所以我无法下载内容urllib2
.我联系了他们,他们在1-2小时内将域名添加到白名单中!
非常感谢并祝贺他们提供优质的服务,即使我使用的是免费套餐.