Yan*_*ski 4 java jpa criteria-api
我使用JPA标准API从日期库中获取记录.我有实体记录,字段dateTime可以为null.我会编码:
public List<Record> find(RecordFilter recordFilter, int page, int pageSize) {
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<Record> criteriaQuery = criteriaBuilder.createQuery(Record.class);
Root<Record> recordRoot = criteriaQuery.from(Record.class);
/*
* JOINS. Left Joins are used for optional fields, or fields inside of the optional fields.
*/
Join<Record, Agency> recordAgencyJoin = recordRoot.join(RecordTable.FIELD_AGENCY);
//Some other joins
//This is where I had the problem.
applyOrderBy(criteriaQuery, criteriaBuilder, recordRoot);
/*
* Specify which columns to select and their order.
* criteriaQuery.multiselect(....);
*/
applyMultiSelect(recordRoot, recordAgencyJoin, /*other joins*/ criteriaQuery);
/*
* criteriaQuery.where(somePredicate);
*/
applyFilter(recordFilter, criteriaQuery, criteriaBuilder,
recordRoot, recordAgencyJoin /*, other joins*/);
TypedQuery<Record> query = entityManager.<Record>createQuery(criteriaQuery);
RepositoryUtils.applyPagination(query, page, pageSize);
return query.getResultList();
}
private void applyOrderBy(CriteriaBuilder criteriaBuilder, Root<Record> recordRoot, CriteriaQuery<Record> criteriaQuery) {
//Other fields to be added to the final sort.
Order dateTimeDescOrder = criteriaBuilder.desc(recordRoot.get(RecordTable.FIELD_DATE_TIME));
criteriaQuery.orderBy(dateTimeDescOrder /*, other orders by*/);
}
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事实证明,首先显示具有NULL dateTimeField的记录.我使用Postrgres数据库.我会回答这个问题,因为我找到了解决方案.这是一篇类似的帖子. JPA Criteria查询API并最后按null排序
Yan*_*ski 10
在这里,我回答了这个任务.
首先,Postgres默认首先返回null.
SELECT * FROM record ORDER BY date_time_field DESC;
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SELECT * FROM record ORDER BY date_time_field DESC NULLS LAST;
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其次,我不得不改变applyOrderBy方法
private void applyOrderBy(CriteriaBuilder criteriaBuilder, Root<Record> recordRoot, CriteriaQuery<Record> criteriaQuery) {
//In the class code
//private static final Date MIN_DATE = new Date(0L);
final Date MIN_DATE = new Date(0L);
//We treat records will NULL dateTimeField as if it was MIN_DATE.
Order dateTimeDescOrder = criteriaBuilder.desc(
//NULL values - last - WORKAROUND.
criteriaBuilder.coalesce(recordRoot.get(RecordTable.FIELD_DATE_TIME), MIN_DATE));
criteriaQuery.orderBy(dateTimeDescOrder);
}
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注意,来自hibernate-jpa-2.1的CriteriaBuilder.
/**
* Create an expression that returns null if all its arguments
* evaluate to null, and the value of the first non-null argument
* otherwise.
*
* @param x expression
* @param y value
*
* @return coalesce expression
*/
<Y> Expression<Y> coalesce(Expression<? extends Y> x, Y y);
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