我有以下时间服务:
start = pd.to_datetime('2016-1-1')
end = pd.to_datetime('2016-1-15')
rng = pd.date_range(start, end, freq='2h')
df = pd.DataFrame({'timestamp': rng, 'values': np.random.randint(0,100,len(rng))})
df = df.set_index(['timestamp'])
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我想删除这两个时间戳之间的行:
start_remove = pd.to_datetime('2016-1-4')
end_remove = pd.to_datetime('2016-1-8')
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我怎样才能做到这一点?
运用 query
df.query('index < @start_remove or index > @end_remove')
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运用 loc
df.loc[(df.index < start_remove) | (df.index > end_remove)]
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使用日期切片
这包括终点
pd.concat([df[:start_remove], df[end_remove:]])
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并没有终点
pd.concat([df[:start_remove], df[end_remove:]]).drop([start_remove, end_remove])
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df = df.drop(pd.date_range('2018-01-01', '2018-02-01')), errors='ignore')
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