Far*_*ris 5 angular2-routing angular
Routs策略:
export const routes = [
{
path : 'rto-activation/:id',
component : RtoActivationComponent,
resolve : {
'singleRto': SingleRtoResolve
},
children : [
{path: 'start', component: ActivationStartComponent},
{path: 'warning', component: WarningComponent},
{path: 'confirm', component: ConfirmRtoDetailsComponent},
{path: 'ldWaiver', component: LDWaiverComponent},
{path: 'payment-schedule', component: PaymentScheduleComponent},
{path: 'user-reference', component: ReferenceComponent}
]
}
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SingleRtoResolve:
constructor(private router: Router,
private route: ActivatedRoute) {
}
resolve() {
var self = this;
return new Promise((resolve, reject) => {
self.subscription = self.route.params.subscribe(
(param: any) => {
let id = param[ 'id' ];
self.rtoService.getRto(null, +id)
.then((res: any) => {
resolve(res)
})
});
});
}
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我知道:我们通常从ActivatedRoute服务获得params.
问题:我可以从路由器服务获得参数.
简介:尝试在Resolve Injectable上获取路径参数,因为在该阶段路线未激活且我无法获得参数.
用例:当用户使用某些(:id)打开任何子路由(隐含和显式)时,应该在父路由中解析数据.
在任何子组件中激活路由时,可以成功获取Params:
ngOnInit() {
let self = this;
this.subscription = this.route.params.subscribe(
(param: any) => {
let id = param[ 'id' ];
self.rtoService.getRto(null, +id)
.then((res: any) => {
})
});
}
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你SingleRtoResolve应该的implements Resolve<T>.然后你只需要你的数据服务(RtoService我猜)constructor() {}.不需要Router或在ActivatedRoute这里,因为你resolve()会得到一个ActivatedRouteSnapshot和一个RouterStateSnapshot.所以resolve()看起来会像那样:
resolve(
route: ActivatedRouteSnapshot, state: RouterStateSnapshot
): Promise<any> {
return ...
}
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..你可以route.params['id']用来获取你的身份.
编辑:您还可以查看Resolve的文档
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