pat*_*rat 1 loops user-input r vector
我编写了以下循环来将用户输入(可以是单个,两个或三个数字)转换为所有三位数字; 这样输入矢量[7,8,9,10,11]将被转换成输出矢量[007,008,009,010,011].这是我的代码:
zeroes <- function(id){
for(i in 1:length(id)){
if(id[i] <= 9){
id[i] <- paste("00", id[i], sep = "")
}
else if(id[i] >= 10 && id[i] <= 99){
id[i] <- paste("0", id[i], sep = "")
}
}
id
}
Run Code Online (Sandbox Code Playgroud)
对于输入向量
id <- 50:100
Run Code Online (Sandbox Code Playgroud)
我得到以下输出:
[1] "050" "0051" "0052" "0053" "0054" "0055" "0056" "0057" "0058" "0059"
[11] "0060" "0061" "0062" "0063" "0064" "0065" "0066" "0067" "0068" "0069"
[21] "0070" "0071" "0072" "0073" "0074" "0075" "0076" "0077" "0078" "0079"
[31] "0080" "0081" "0082" "0083" "0084" "0085" "0086" "0087" "0088" "0089"
[41] "090" "091" "092" "093" "094" "095" "096" "097" "098" "099"
[51] "00100"
Run Code Online (Sandbox Code Playgroud)
所以,对于id [1]看起来这个函数是有效的,那么下面的数字就有一个bug,但对于id [41:50],我又得到了正确的输出.我无法弄清楚为什么会这样,我做错了什么.任何建议都受到热烈欢迎.
这是因为当你id在函数中进行第一次替换时,向量变为字符(因为向量不能存储数字和字符).
所以,zeroes(51)正常工作:
> zeroes(51)
[1] "051"
Run Code Online (Sandbox Code Playgroud)
但如果它是第二个项目,则失败:
> zeroes(c(50,51))
[1] "050" "0051"
Run Code Online (Sandbox Code Playgroud)
因为当你的循环进入51时,其实际上是"51"的引号.那失败了:
> zeroes("51")
[1] "0051"
Run Code Online (Sandbox Code Playgroud)
因为"51"小于9:
> "51"<9
[1] TRUE
Run Code Online (Sandbox Code Playgroud)
因为R将9转换为"9"然后进行字符比较,所以在整理顺序字母表中只有"5"与"9"进行比较而"5"在"9"之前.
其他语言可能会将字符"51"转换为数字,然后与数字9进行比较,并说"51"<9为False,但R就是这样做的.
课程:不要覆盖输入向量!(和使用sprintf).