0 c# select dialog path openfiledialog
您好,我正在尝试从 Windows 窗体应用程序的目录中选择一个文件,但我似乎找不到任何可以从文本框中删除路径并仅保留文件名的内容(例如:“C:\Users\ Users\Documents\File.txt”将只是“File.txt”),它在选择文件时保存输出。
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = @"C:\OUTPUT";
openFileDialog1.Title = "Browse exe Files";
openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
openFileDialog1.Filter = "exe files | *.exe";
openFileDialog1.DefaultExt = "exe";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
openFileDialog1.ReadOnlyChecked = true;
openFileDialog1.ShowReadOnly = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
textBox6.Text = openFileDialog1.FileName;
}
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谁能启发我如何做到这一点?
谢谢
为此,您可以使用Path.GetFileName函数。
textBox6.Text = System.IO.Path.GetFileName(openFileDialog1.FileName);
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