HTML/Javascript表单复选框值未显示

Question

相当直接的问题.

当用户点击"添加"按钮并选中复选标记时,我希望在class ="household"中说出"吸烟者"的值.

如果未选中复选标记,我希望值为"非吸烟者"

目前,我的"if else"声明没有解雇.一直在寻找解决这个问题.有人可以帮忙吗？

附注:没有jQuery,无法编辑HTML.只有纯Javascript.

HTML

<ol class="household"></ol>
    <form>
        <div>
            <label>Age
                <input type="text" name="age">
            </label>
        </div>
        <div>
            <label>Relationship
                <select name="rel">
                    <option value="">---</option>
                    <option value="self">Self</option>
                    <option value="spouse">Spouse</option>
                    <option value="child">Child</option>
                    <option value="parent">Parent</option>
                    <option value="grandparent">Grandparent</option>
                    <option value="other">Other</option>
                </select>
            </label>
        </div>
        <div>
            <label>Smoker?
                <input type="checkbox" name="smoker">
            </label>
        </div>
        <div>
            <button class="add">add</button>
        </div>
        <div>
            <button type="submit">submit</button>
        </div>
    </form>

JS

 function validate(form) {

        fail = validateAge(form.age.value)
        fail += validateRel(form.rel.value)

        if (fail == "") return true
        else {
            alert(fail);
            return false
        }
    }

    function validateAge(field) {
        if (isNaN(field)) return "No age was entered. \n"
        else if (field < 1 || field > 200)
            return "Age must be greater than 0. \n"
        return ""
    }

    function validateRel(field) {
        if (field == "") return "Please select a relationship \n"
        return ""

    }


    document.querySelector("form").onsubmit = function() {
        return validate(this)

    }



    document.querySelector(".add").onclick = function(event) {
        event.preventDefault();
        createinput()


    }


    count = 0;

    function createinput() {
        field_area = document.querySelector('.household')
        var li = document.createElement("li");
        var p1 = document.createElement("p");
        var p2 = document.createElement("p");
        var p3 = document.createElement("p");
        var x = document.getElementsByName("age")[0].value;
        var y = document.getElementsByName("rel")[0].value;
        var z = document.getElementsByName("smoker")[0].value.checked;


        if( z === undefined) {
            return ("Non smoker \n")

        }
        else {
           return ("Smoker \n")

        }


        p1.innerHTML = x;
        p2.innerHTML = y;
        p3.innerHTML = z;
        li.appendChild(p1);
        li.appendChild(p2);
        li.appendChild(p3);
        field_area.appendChild(li);
        //removal link
        var removalLink = document.createElement('a');
        removalLink.onclick = function() {
            this.parentNode.parentNode.removeChild(this.parentNode)
        }
        var removalText = document.createTextNode('Remove Field');
        removalLink.appendChild(removalText);
        li.appendChild(removalLink);
        count++
    }

Answer 1

第一个问题是你没有正确地获得复选框状态.它应该是document.getElementsByName("smoker")[0].checked代替document.getElementsByName("smoker")[0].value.checked.

第二个问题是你用过return的if else.如果您使用,return则不会执行该功能的以下代码.

更改

var z = document.getElementsByName("smoker")[0].value.checked;

if( z === undefined) {
    return ("Non smoker \n")
}
else {
    return ("Smoker \n")
}

至

var z = document.getElementsByName("smoker")[0].checked;

if (!z) {
    z = "Non smoker \n";
} else {
    z = "Smoker \n";
}