Vla*_*ius 102 python string enums serialization type-conversion
我想知道将字符串转换(反序列化)到Python的Enum类的正确方法是什么.好像getattr(YourEnumType, str)工作似乎,但我不确定它是否足够安全.
更具体地说,我想将'debug'字符串转换为Enum对象,如下所示:
class BuildType(Enum):
debug = 200
release = 400
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Eth*_*man 151
此功能已内置于Enum [1]中:
>>> from enum import Enum
>>> class Build(Enum):
... debug = 200
... build = 400
...
>>> Build['debug']
<Build.debug: 200>
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[1]官方文件: Enum programmatic access
rog*_*err 14
另一种选择(如果你的字符串不映射1-1到您的枚举的情况下特别有用)是一个添加staticmethod到您的Enum,如:
class QuestionType(enum.Enum):
MULTI_SELECT = "multi"
SINGLE_SELECT = "single"
@staticmethod
def from_str(label):
if label in ('single', 'singleSelect'):
return QuestionType.SINGLE_SELECT
elif label in ('multi', 'multiSelect'):
return QuestionType.MULTI_SELECT
else:
raise NotImplementedError
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那你可以做 question_type = QuestionType.from_str('singleSelect')
我的类似Java的问题解决方案。希望它可以帮助某人...
from enum import Enum, auto
class SignInMethod(Enum):
EMAIL = auto(),
GOOGLE = auto()
@classmethod
def value_of(cls, value):
for k, v in cls.__members__.items():
if k == value:
return v
else:
raise ValueError(f"'{cls.__name__}' enum not found for '{value}'")
sim = SignInMethod.value_of('EMAIL')
assert sim == SignInMethod.EMAIL
assert sim.name == 'EMAIL'
assert isinstance(sim, SignInMethod)
# SignInMethod.value_of("invalid sign-in method") # should raise `ValueError`
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def custom_enum(typename, items_dict):
class_definition = """
from enum import Enum
class {}(Enum):
{}""".format(typename, '\n '.join(['{} = {}'.format(k, v) for k, v in items_dict.items()]))
namespace = dict(__name__='enum_%s' % typename)
exec(class_definition, namespace)
result = namespace[typename]
result._source = class_definition
return result
MyEnum = custom_enum('MyEnum', {'a': 123, 'b': 321})
print(MyEnum.a, MyEnum.b)
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还是需要将字符串转换为已知的 Enum?
class MyEnum(Enum):
a = 'aaa'
b = 123
print(MyEnum('aaa'), MyEnum(123))
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要么:
class BuildType(Enum):
debug = 200
release = 400
print(BuildType.__dict__['debug'])
print(eval('BuildType.debug'))
print(type(eval('BuildType.debug')))
print(eval(BuildType.__name__ + '.debug')) # for work with code refactoring
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