在 Python 中为换行符添加缺失的句点

Question

我想用 Python 编写一个正则表达式来执行以下操作

转换所有以“.”结尾的句子[alphanumeric]\n并将其替换为“。”

例如

I went there
I also went there.
It is


That-
I too went there!
It went there?
It is 3

所以假设我们有

应转换为

I went there.
I also went there.
It is.


That-
I too went there!
It went there?
It is 3.

我怎样才能做到这一点？

编辑：输入字符串是

s = "I went there\nI also went there.\nIt is\n\nThat-\nI too went there!\nIt went there?\nIt is 3"

还， ”？” 不应附加“.”

EDIT2：我修改了示例，使其包含一个 double\n和一个以 结尾的句子-。因此“-”不应附加“.”。

Answer 1

尝试这样的事情：

s = 'I went there'

if s[-1] not in ['!', ',', '.', '\n']:
    s += '.'

编辑：

根据您的新输入，以下操作应该有效：

new_string = ''.join('{}.\n'.format(item) if (item and item[-1] not in '!?.,-') else '{}\n'.format(item) for item in s.split('\n'))

如果您不想要\n末尾的new_string，可以将其删除：

new_string = new_string.rstrip('\n')

输出：

>>> s = "I went there\nI also went there.\nIt is\n\nThat-\nI too went there!\nIt went there?\nIt is 3"
>>> new_string = ''.join('{}.\n'.format(item) if (item and item[-1] not in '!?.,-') else '{}\n'.format(item) for item in s.split('\n'))
>>>
>>> print(new_string)
I went there.
I also went there.
It is.

That-
I too went there!
It went there?
It is 3.