Gui*_*uig 5 static class subclass instantiation swift
我有静态函数来实例化看起来像的视图控制器
class AController: UIViewController {
static func instantiate() -> AController {
let storyboard = UIStoryboard(name: "AController", bundle: nil)
let controller = s.instantiateInitialViewController() as? AController
return controller!
}
}
class BController: UIViewController {
static func instantiate() -> BController {
let storyboard = UIStoryboard(name: "BController", bundle: nil)
let controller = storyboard.instantiateInitialViewController() as? BController
return controller!
}
}
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我有一堆,所以我想让它更干净:
class MYViewController: UIViewController {
class func instantiate() -> self.type {
let storyboard = UIStoryboard(name: "\(self.type)", bundle: nil)
let controller = storyboard.instantiateInitialViewController() as? self.type
return controller!
}
}
class AController: MYViewController {
}
class BController: MYViewController {
}
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但是我不知道在静态/类函数中动态引用对象的类型,以及从子类调用时如何让 this 引用子类。一旦对象被实例化,就很容易做到type(of: object)
尝试这个:
class MYViewController: UIViewController {
class func instantiate() -> Self {
let storyboard = UIStoryboard(name: "\(self)", bundle: nil)
let controller = storyboard.instantiateInitialViewController() as! Self
return controller
}
}
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我不是 100% 确定它有效,因为我没有直接测试你的代码(不想创建一个故事板只是为了测试),但我编写了类似的代码来测试它,它有效:
class MYViewController: UIViewController {
class func instantiate() -> Self {
print("type: \(self)")
return self.init()
}
}
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