如何改变按下的按钮颜色？

Question

我有3对按钮命名(one,numOne),(two,numTwo),(three,numThree).最初tintColor的所有按钮都是black.我想改变一对按钮的颜色,blue如果这些按钮中的一个按钮被轻敲,并且black当其他对被轻敲时返回.我可以通过以下代码来实现它,但是还有其他最短的方式吗？

@IBOutlet weak var one: UIButton!
@IBOutlet weak var two: UIButton!
@IBOutlet weak var three: UIButton!
@IBOutlet weak var numOne: UIButton!
@IBOutlet weak var numTwo: UIButton!
@IBOutlet weak var numThree: UIButton!

 @IBAction func buttonTapped(_ sender: UIButton) {
        if sender == one || sender == numOne
        {
            one.tintColor = UIColor.blue
            numOne.tintColor = UIColor.blue
            two.tintColor = UIColor.black
            numTwo.tintColor = UIColor.black
            three.tintColor = UIColor.black
            numThree.tintColor = UIColor.black

    }
   else if sender == two || sender == numTwo
    {
        two.tintColor = UIColor.blue
        numTwo.tintColor = UIColor.blue
        one.tintColor = UIColor.black
        numOne.tintColor = UIColor.black
        three.tintColor = UIColor.black
        numThree.tintColor = UIColor.black

    }
    else
    {
        three.tintColor = UIColor.blue
        numThree.tintColor = UIColor.blue
         two.tintColor = UIColor.black
        numTwo.tintColor = UIColor.black
        one.tintColor = UIColor.black
        numOne.tintColor = UIColor.black

    }
   }

Answer 1

var allButtons: [[UIButton]] = [[one, numOne], [two, numTwo], [three, numThree]]

func tap(_ sender: UIButton) {
    allButtons.forEach { buttons in
        if buttons.contains(sender) {
            buttons.forEach{ $0.tintColor = .blue }
        } else {
            buttons.forEach{ $0.tintColor = .black }
        }
    }
}

XD越短

buttons.contains(sender) ? buttons.forEach{ $0.tintColor = .blue } : buttons.forEach{ $0.tintColor = .black }