更改行名称等于列名称的矩阵的值

Question

我试图更改矩阵的值,以便对于行名称等于列名称的每个元素,结果矩阵的值为1.

> z<-matrix(0, nrow=10, ncol=8)
> colnames(z)<-letters[1:8]
> rownames(z)<-c("f", "c", "a", "f", "a", "b", "f", "b", "h", "c")
> z
  a b c d e f g h
f 0 0 0 0 0 0 0 0
c 0 0 0 0 0 0 0 0
a 0 0 0 0 0 0 0 0
f 0 0 0 0 0 0 0 0
a 0 0 0 0 0 0 0 0
b 0 0 0 0 0 0 0 0
f 0 0 0 0 0 0 0 0
b 0 0 0 0 0 0 0 0
h 0 0 0 0 0 0 0 0
c 0 0 0 0 0 0 0 0

z应该是:

  a b c d e f g h
f 0 0 0 0 0 1 0 0
c 0 0 1 0 0 0 0 0
a 1 0 0 0 0 0 0 0
f 0 0 0 0 0 1 0 0
a 1 0 0 0 0 0 0 0
b 0 1 0 0 0 0 0 0
f 0 0 0 0 0 1 0 0
b 0 1 0 0 0 0 0 0
h 0 0 0 0 0 0 0 1
c 0 0 1 0 0 0 0 0

我试过了:

> z[unique(rownames(z)), unique(rownames(z))]<-1
> z
  a b c d e f g h
f 1 1 1 0 0 1 0 1
c 1 1 1 0 0 1 0 1
a 1 1 1 0 0 1 0 1
f 0 0 0 0 0 0 0 0
a 0 0 0 0 0 0 0 0
b 1 1 1 0 0 1 0 1
f 0 0 0 0 0 0 0 0
b 0 0 0 0 0 0 0 0
h 1 1 1 0 0 1 0 1
c 0 0 0 0 0 0 0 0

和:

> z["a", "a"]<-1
> z
  a b c d e f g h
f 0 0 0 0 0 0 0 0
c 0 0 0 0 0 0 0 0
a 1 0 0 0 0 0 0 0
f 0 0 0 0 0 0 0 0
a 0 0 0 0 0 0 0 0
b 0 0 0 0 0 0 0 0
f 0 0 0 0 0 0 0 0
b 0 0 0 0 0 0 0 0
h 0 0 0 0 0 0 0 0
c 0 0 0 0 0 0 0 0

但这只改变了'a'栏中的第一个'a'.

Answer 1

您也可以使用base R执行此操作outer.

z[outer(rownames(z), colnames(z), "==")] <- 1
z
  a b c d e f g h
f 0 0 0 0 0 1 0 0
c 0 0 1 0 0 0 0 0
a 1 0 0 0 0 0 0 0
f 0 0 0 0 0 1 0 0
a 1 0 0 0 0 0 0 0
b 0 1 0 0 0 0 0 0
f 0 0 0 0 0 1 0 0
b 0 1 0 0 0 0 0 0
h 0 0 0 0 0 0 0 1
c 0 0 1 0 0 0 0 0