如何在Java中使用XSLT 2.0和XSLT 3.0？

Question

我可以在Java中使用XSLT 1.0,如下面的示例所示: -

copy.xml

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?>
<catalog>
    <book id="bk101">
        <author>Gambardella, Matthew</author>
        <title>XML Developer's Guide</title>
        <genre>Computer</genre>
        <price>44.95</price>
        <publish_date>2000-10-01</publish_date>        
        <description>An in-depth look at creating applications with
 XML.</description>
    </book>
    <book id="bk102">
        <author>Ralls, Kim</author>
        <title>Midnight Rain</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-12-16</publish_date>
        <description>A former architect battles corporate zombies,
 an evil sorceress, and her own childhood to become queen of the
 world.</description>
    </book>
    <book id="bk103">
        <author>Corets, Eva</author>
        <title>Maeve Ascendant</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-11-17</publish_date>
        <description>After the collapse of a nanotechnology society
 in England, the young survivors lay the foundation for a new 
society.</description>
    </book>
</catalog>

copy.xsl

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/ | @* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

Copy.java

package com.data.transform;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class Copy {

    public static void main(String args[]) throws Exception {
        StreamSource source = new StreamSource("copy.xml");
        StreamSource stylesource = new StreamSource("copy.xsl");

        TransformerFactory factory = TransformerFactory.newInstance();
        Transformer transformer = factory.newTransformer(stylesource);

        StreamResult result = new StreamResult(System.out);
        transformer.transform(source, result);
      }
}

产量

<?xml version="1.0" encoding="UTF-8"?><?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?><catalog>
    <book id="bk101">
        <author>Gambardella, Matthew</author>
        <title>XML Developer's Guide</title>
        <genre>Computer</genre>
        <price>44.95</price>
        <publish_date>2000-10-01</publish_date>        
        <description>An in-depth look at creating applications with
 XML.</description>
    </book>
    <book id="bk102">
        <author>Ralls, Kim</author>
        <title>Midnight Rain</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-12-16</publish_date>
        <description>A former architect battles corporate zombies,
 an evil sorceress, and her own childhood to become queen of the
 world.</description>
    </book>
    <book id="bk103">
        <author>Corets, Eva</author>
        <title>Maeve Ascendant</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-11-17</publish_date>
        <description>After the collapse of a nanotechnology society
 in England, the young survivors lay the foundation for a new 
society.</description>
    </book>
</catalog>

但是,现在我想使用包含在XSLT 2.0和XSLT 3.0(如几件事情xsl:analyze-string,xsl:try等)在Java中.我怎样才能做到这一点 ？

Answer 1

从Maven或Sourceforge获取Saxon 9 HE 并将其放在类路径上,然后在9.8之前使用Saxon 9.x支持XSLT 2.0或支持XSLT 3.0(流式传输,高阶函数xsl:evaluate,模式感知,向后兼容性除外)与9.8 .要获得完整的XSLT 3.0支持,您需要从Saxonica下载Saxon 9 PE或EE,并将其与您购买的许可证或您在类路径上请求的试用许可证放在一起.